我有一张很大的(比方说)用户表,他们访问各种网页。该表的一个例子可以是:
schema.page_views
date| user_id| webpage|
----------+---------+----------------+
01/05/2012|aaaaaaaaa|www.example1.com|
01/06/2012|aaaaaaaaa|www.example2.com|
01/06/2012|ababababa|www.example1.com|
...
01/05/2013|aaaaaaaaa|www.example2.com|
01/05/2013|ababababa|www.example1.com|
03/05/2013|aaaaaaaaa|www.example2.com|此外,我还有一个日历查找表:
schema.weeks
week_number| begin_date| end_date|year|
-----------+-----------+-----------+----+
18| 2012-04-23| 2012-04-30|2012|
17| 2012-04-15| 2012-04-22|2012|
16| 2012-04-08| 2012-04-14|2012|我最终想从这两张表格中获得三个星期的页面浏览量。更具体地说,如果我今天发出这个查询,我想要的内容如下:
webpage| 1-3| 4-6| 7-9| 10-12|
----------------+-------+-------+-------+-------+
www.example1.com| 124875| 175682| 168542| 159780|
www.example2.com| three week period numbers |其中“1-3”指的是最近的三周,“4-6”指的是四到六周前,等等。
到目前为止,我已经获得了每个网站和周的每周总页面浏览量如下:
-- join to get begin and end_dates
with t1 as (
select a.*, b.* from schema.page_views a
join schema.weeks b
on a.date between b.begin_date and b.end_date),
-- now aggregate per week
weekly_vol as (
select webpage, year, week_number, begin_date, end_date,
count(*) volume
from t1
group by 1, 2, 3, 4, 5)
select * from weekly_vol limit 1;举个例子,
webpage| year| week_number| begin_date| end_date| volume|
----------------+-----+------------+-----------+-----------+-------+
www.example1.com| 2012| 18| 2012-04-23| 2012-04-30| 41871|有了这样一张桌子,我怎样才能到达我想要的桌子呢?我曾经想过用类似于on a.week_number between b.week_number and b.week_number + 2的东西来加入它,但是我不认为这个想法会在过去的12周包括新的一年开始的时候起作用。
有没有人做过类似的事情,如果是,你是如何处理这个问题的?关于采取不同办法的建议也将得到同样的赞赏。
发布于 2017-05-06 00:42:52
你的问题有点不清楚。周数是在一年之内还是在所有时间内?您想要数据中相对于上周的金额还是相对于当前日期的金额?
在任何情况下,下面的操作至少与您想要的类似。关键是外部查询中的条件聚合:
with t1 as (
select pv.*, w.*,
max(pv.week_number) over (partition by webpage, year) as last_week_number
from schema.page_views pv join
schema.weeks w
on pv.date between w.begin_date and w.end_date
),
weekly_vol as (
select webpage, year, week_number, begin_date, end_date,
count(*) as volume
from t1
group by webpage, year, week_number, begin_date, end_date
)
select webpage, year,
sum(case when last_week_number - week_number < 3
then volume else 0
end) as week_1_3,
sum(case when last_week_number - week_number >= 3 and last_week_number - week_number < 6
then volume else 0
end) as week_4_6
from weekly_vol
group by webpage, year;https://stackoverflow.com/questions/43813869
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