我有个课
class movie:
def __init__(self, title, year, release):
self._title = title
self._year = year
self._release= release
def getTitle(self):
return self._title
def getYear(self):
return self._year
def getRel(self):
return self._release
def setTitle(self, title):
self._title = movie
def setYear(self, year):
self._year = movie
def setRel(self, release):
self._release = movie
def __str__(self):
outputString = "Title:" + str(self._title) + "Year:" + str(self._year) + "Production:" + str(self._release)
return outputString我想用这个创建一个列表
import movie
mfirst = movie.movie("The Shawshank Redemption", "1994", "Castle Rock Entertainment")
msecond = movie.movie("The Godfather", "1972", "Paramount Pictures")有没有一种方法可以让我分别列出标题、年份和制作工作室?我尝试过不同的方法,但一直收到类似[<movie.movie instance at 0x10117ecf8>]的信息
发布于 2017-05-04 03:00:14
您有用于获取值的setter和getter,因此我们可以利用这一点,对于实例化的每个对象,您可以对所有对象应用统一的查询。
在你的movie.py里
class Movie:
def __init__(self, title, year, release):
self._title = title
self._year = year
self._release= release
def getTitle(self):
return self._title
def getYear(self):
return self._year
def getRel(self):
return self._release
def setTitle(self, title):
self._title = movie
def setYear(self, year):
self._year = movie
def setRel(self, release):
self._release = movie
def __str__(self):
outputString = "Title:" + str(self._title) + "Year:" + str(self._year) + "Production:" + str(self._release)
return outputString在另一个文件中,让我们称之为my_movies.py
from movie import Movie
first_movie = Movie("The Shawshank Redemption", "1994", "Castle Rock Entertainment")
second_movie = Movie("The Godfather", "1972", "Paramount Pictures")
my_movies = [first_movie, second_movie]
titles = []
years = []
releases = []
for m in my_movies:
titles.append(m.getTitle())
years.append(m.getYear())
releases.append(m.getRel())
print('\t'.join(titles))
print('\t'.join(years))
print('\t'.join(releases))https://stackoverflow.com/questions/43773041
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