我正在编写一个函数,其中我使用forM_处理一个列表,并将结果附加到一个TVar列表中:
import Control.Concurrent.STM
import Control.Concurrent.STM.TVar
import Control.Concurrent (forkIO)
import Control.Monad (forM_)
insert :: a -> [a] -> [a]
insert = (:) -- stub
my_func_c :: (a -> a) -> [a] -> IO [a]
my_func_c my_function arr = do
res_var <- atomically $ newTVar ([]::[a])
forkIO $ forM_ arr $ \x -> atomically $ do
let y = id $! my_function x
modifyTVar res_var (insert y)
atomically $ readTVar res_var如果我用-threaded编译它,结果总是空的。怎么可能等待线程完成呢?我不能使用MVar或Async。我必须使用TVar或其他基于TVar的数据结构来解决这个问题。
发布于 2017-04-28 02:13:42
惯用的解决方案是使用TMVars:
my_func_c :: (a -> a) -> [a] -> IO [a]
my_func_c my_function arr = do
res_var <- atomically $ newTVar []
finished <- atomically $ newEmptyTMVar
forkIO $ do
forM_ arr $ \x -> atomically $ do
let y = id $! my_function x
modifyTVar res_var (insert y)
atomically $ putTMVar finished ()
atomically $ takeTMVar finished >> readTVar res_var但是,如果您确实只允许使用TVar,则可以使用TVar Bool模拟TMVar ()。
my_func_c :: (a -> a) -> [a] -> IO [a]
my_func_c my_function arr = do
res_var <- atomically $ newTVar []
finished <- atomically $ newTVar False
forkIO $ do
forM_ arr $ \x -> atomically $ do
let y = id $! my_function x
modifyTVar res_var (insert y)
atomically $ writeTVar finished True
atomically $ waitTVar finished >> readTVar res_var
waitTVar :: TVar Bool -> STM ()
waitTVar tv = do
finished <- readTVar tv
unless finished retry在遮罩下,TVar (Maybe a) (so TMVar () ~ TVar (Maybe ()) ~ TVar Bool)与retry是完全等价的。
https://stackoverflow.com/questions/43669931
复制相似问题