未调用的PHP Prophecy Stub方法

Question

我没办法通过这个明显的考试。Foo在其构造函数中获取Bar，当调用Foo::m()时，Bar::bar()被调用。

use PHPUnit\Framework\TestCase;

class Bar {
    public function bar() {
        echo "BAR";
    }
}

class Foo {
    protected $bar;
    public function __construct($bar) {
        $this->bar= $bar;
    }
    public function m() {
        $this->bar->bar();
    }
}

class FooTest extends TestCase {

    public function testM() {
        $bar = $this->prophesize(Bar::class);
        $bar->bar()->shouldBeCalled();
        $foo = new Foo($bar);
        $foo->m();
    }
}

预言无法注册对bar的调用：：bar()

Some predictions failed:
  Double\Bar\P1:
    No calls have been made that match:
      Double\Bar\P1->bar()
    but expected at least one.

Answer 1

$bar变量包含一个ObjectProphecy实例，该实例与Bar类无关。调用$bar->reveal()以获得一个测试双，这是Bar的扩展

public function testM()
{
    $bar = $this->prophesize(Bar::class);
    $bar->bar()->shouldBeCalled();
    $foo = new Foo($bar->reveal());
    $foo->m();
}