我有一个像这样的python列表:
Category Title ProductId Rating
'Electronics, Books, Bundles' Lautner e-Reader Cover 161553 4
'Electronics, Books, Bundles' Lautner stand in e-Reader Cover 161552 3
'Electronics, Books, Bundles' Lautner Chocolate NOOK Case 594451 5
'Electronics, Books, Bundles' Oliver e-Reader Cover 161685 1
'Electronics, Books, Covers' Dessin Leather Cover for Nook Color; Nook Tablet Digital Reader 594033 4.3
'Electronics, Books, Covers' Emerson Quote e-Reader Cover 161542 2.8
'Electronics, Books, Covers' Industriell Easel e-Reader Cover 161682 3.7
'Electronics, Books, Covers' Jonathan Adler Book Reader Cover Hd - Elephant 594548 4.9
'Electronics, Scanners, Covers' Lyra Light Front Cover for NOOK eR 161683 4
'Electronics, Scanners, Covers' Nook Tablet Dessin Cover in Marine 161686 3.8
'Electronics, Scanners, Covers' Nook Tablet Horizontal Stand Cover in Red 594202 4.2
'Electronics, Scanners, Covers' Canvas Bella Library Cover 161554 3
'Electronics, Books, Radios' Groovy Protective Stand Cover: Custom Designed for 7-inch NOOK HD 594549 3.8
'Electronics, Books, Radios' Hd Groovy Stand In Blue- Nook 594514 4.1
'Electronics, Books, Radios' Hutton Envelope in Bark 161560 2.9
'Electronics, Books, Radios' Italian Leather-Style Chesterton Cover for NOOK Reader 161561 4在所有这些列表值中,我想要每个类别中的顶部k。前2名应提供以下结果:
'Electronics, Books, Bundles' Lautner Chocolate NOOK Case 594451 5
'Electronics, Books, Bundles' Lautner e-Reader Cover 161553 4
'Electronics, Books, Covers' Jonathan Adler Book Reader Cover Hd - Elephant 594548 4.9
'Electronics, Books, Covers' Dessin Leather Cover for Nook Color; Nook Tablet Digital Reader 594033 4.3
'Electronics, Books, Radios' Hd Groovy Stand In Blue- Nook 594514 4.1
'Electronics, Books, Radios' Italian Leather-Style Chesterton Cover for NOOK Reader 161561 4
'Electronics, Scanners, Covers' Nook Tablet Horizontal Stand Cover in Red 594202 4.2
'Electronics, Scanners, Covers' Lyra Light Front Cover for NOOK eR 161683 4添加我尝试过的东西:
sorted_data = sorted(data, key=operator.itemgetter(1), reverse=True)
k = int(sys.argv[1])
for result in sorted_data[:k]:
print result这里,我将'k‘作为命令行参数传递给python文件。
发布于 2017-04-23 09:59:37
使用迭代器等,您可以获得相对高效的性能。注意:这使用了标准的Python库。
import heapq
import itertools
# group by 'Category'
groups = itertools.groupby(some_list, key=lambda element: element[0])
# take top two of each group based on 'Rating'
top_two_of_each = (heapq.nlargest(2, values, key=lambda value: value[3]) for
_, values in groups)
# flatten the nested iterators
top_two_of_each_flattened = itertools.chain(*top_two_of_each)
# convert iterator into a list
top_two_of_each_flattened_as_list = list(top_two_of_each_flattened)发布于 2017-04-23 09:20:01
这可能是你所需要的:
data = ''''Electronics, Books, Bundles' Lautner e-Reader Cover 161553 4
'Electronics, Books, Bundles' Lautner stand in e-Reader Cover 161552 3
'Electronics, Books, Bundles' Lautner Chocolate NOOK Case 594451 5
'Electronics, Books, Bundles' Oliver e-Reader Cover 161685 1
'Electronics, Books, Covers' Dessin Leather Cover for Nook Color; Nook Tablet Digital Reader 594033 4.3
'Electronics, Books, Covers' Emerson Quote e-Reader Cover 161542 2.8
'Electronics, Books, Covers' Industriell Easel e-Reader Cover 161682 3.7
'Electronics, Books, Covers' Jonathan Adler Book Reader Cover Hd - Elephant 594548 4.9
'Electronics, Scanners, Covers' Lyra Light Front Cover for NOOK eR 161683 4
'Electronics, Scanners, Covers' Nook Tablet Dessin Cover in Marine 161686 3.8
'Electronics, Scanners, Covers' Nook Tablet Horizontal Stand Cover in Red 594202 4.2
'Electronics, Scanners, Covers' Canvas Bella Library Cover 161554 3
'Electronics, Books, Radios' Groovy Protective Stand Cover: Custom Designed for 7-inch NOOK HD 594549 3.8
'Electronics, Books, Radios' Hd Groovy Stand In Blue- Nook 594514 4.1
'Electronics, Books, Radios' Hutton Envelope in Bark 161560 2.9
'Electronics, Books, Radios' Italian Leather-Style Chesterton Cover for NOOK Reader 161561 4'''
groups = [item.split("' ") for item in data.split('\n')]
grouped_data = {}
for group in groups:
item = [group[1].strip()]
group = group[0].strip("'")
if group not in grouped_data:
grouped_data[group] = item
else:
grouped_data[group] += item
def topN(data, n):
data = [item.split() for item in data]
data = sorted(data, key=lambda x: float(x[-1]), reverse=True)[:n]
data = [' '.join(item) for item in data]
return data
result = {}
for k, v in grouped_data.items():
result[k] = topN(v, 2)
final_result = [': '.join([group1, item1]) for group1, value1 in result.items() for item1 in value1]发布于 2017-04-23 09:41:29
也许不是一个有效但可以理解的解决方案:
您想要每个元素的最高结果,所以首先我们需要识别元素。我们通过在'上拆分来实现这一点,因为这是最简单的指示符,第一个'中的空字符串将被丢弃(1:)。
separated = [element.split("'")[1:] for element in data]由于我们对第一个字符串标识的项感兴趣,字典似乎是一个合适的数据结构。
from collections import defaultdict
data_dict = defaultdict(list)
for line in separated:
data_dict[line[0]].append(line)现在我们有了一种很好的格式,可以对二叉树进行排序。
data_dict.keys():data_dictkey.sort(key=lambda key_string: key_string.split()-1,reverse=True)中的密钥
从这本词典中可以很容易地复制我们的结果:
k = 2
results = []
for key in data_dict.keys():
results.extend(data_dict[key][:k])关键是要使用合适的数据结构,这里有一个字典。这里有一个简短的解决方案:
# make a dict
from collections import defaultdict
data_dict = defaultdict(list)
for line in data:
data_dict[line.split("'")[1]].append(line)
# function working on the dict:
def top_results(data_dict, k):
results = []
for key in data_dict.keys():
results.extend(data_dict[key][:k])
return results但是,更适合继续使用字典,而不是返回不合适的列表。
概括地说:
dict。split("'")将为此工作list.sort对您的列表进行排序。key是必需的,这里我们只使用最后一个单词str.split()[-1],因为这是您的排名。https://stackoverflow.com/questions/43568995
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