我试图通过一个例子来理解计数信号量的概念。但是我想在Linux中使用SysV来实现这一点。
我熟悉二进制信号量和计数信号量的理论部分。
我已经提到了这个链接。
从概念上讲,信号量被用作从一个进程到另一个进程的信号机制,因此我试图编写一个简单的程序。
在下面的程序中,我希望thread_1等待,直到它没有从thread_2得到一个信号,类似地,thread_2应该等到它没有从thread_3得到一个信号。
所以输出应该如下所示:Hello From thread 3 Hello from thread 2 Hello from thread 1
我知道可以正确地使用pthread_join()来实现它,但是我想使用信号量来实现它。
代码:
#include <stdio.h>
#include <unistd.h>
#include <pthread.h>
#include <sys/types.h>
#include <sys/ipc.h>
#include <sys/sem.h>
#include <errno.h>
int sem_id;
struct sembuf sops[3];
void thread_1(void)
{
sops[0].sem_num = 0;
sops[0].sem_op = 0;
sops[0].sem_flg = 0;
if(semop(sem_id, sops, 1) < 0)
perror("Semop In thread 3");
else
printf("Hello From thread 1\n");
}void thread_2(void)
{
sops[0].sem_num = 0;
sops[0].sem_op = -1;
sops[0].sem_flg = 0;
if(semop(sem_id, sops, 1) < 0)
perror("Semop In thread 2");
else
printf("Hello from thread 2\n");
}void thread_3(void)
{
sops[0].sem_num = 0;
sops[0].sem_op = -1;
sops[0].sem_flg = 0;
if(semop(sem_id, sops, 1) < 0)
perror("Semop In thread 3");
else
printf("Hello from thread 3\n");
}int main(void)
{
void (*funct[]) = {thread_1, thread_2, thread_3};
key_t semkey;
char i;
union semun {
int val; /* Value for SETVAL */
struct semid_ds *buf; /* Buffer for IPC_STAT, IPC_SET */
unsigned short *array; /* Array for GETALL, SETALL */
struct seminfo *__buf; /* Buffer for IPC_INFO
(Linux-specific) */
}arg;
pthread_t thread_id[3];
semkey = ftok("/tmp", 'a');
if(semkey < 0)
perror("Cannot Create Semaphore Key");
else
{
sem_id = semget(semkey, 1, (IPC_CREAT|IPC_EXCL|0666));
if(sem_id < 0)
perror("Cannot create semaphore\n");
else
{
arg.val = 3;
if (semctl(sem_id, 0, SETVAL, arg) == -1) {
perror("semctl");
exit(1);
}
}
}
for(i = 0; i < 3; i++)
{
if(pthread_create(&thread_id[i], NULL, funct[i], NULL) < 0)
perror("Cannot Create thread\n");
}
for(i = 0; i < 3; i++)
pthread_join(thread_id[i], NULL);
if(semctl(sem_id, 0, IPC_RMID, NULL) == -1)
perror("semctl");
return 0;
}我是否必须使用多个信号量集来实现我所要做的事情?
发布于 2017-04-21 17:59:51
您需要两个带有计数1的互斥/信号量。假设您的线程名为t0,t1,t2,您的信号量为sem0和sem1,那么t0可以自由运行并递增sem0,t1等待sem0和增量sem1,t2等待sem1。
这里有一个完整的草案,没有错误检查:
#include <stdio.h>
#include <unistd.h>
#include <pthread.h>
#include <sys/types.h>
#include <sys/ipc.h>
#include <sys/sem.h>
#include <errno.h>
static int sem0, sem1;
#define POST1(Sem) semop(Sem, &(struct sembuf){0,1,0}, 1)
#define WAIT1(Sem) semop(Sem, &(struct sembuf){0,-1,0}, 1)
static void* t0(void *unused) { puts("hello from t0"); POST1(sem0); return 0; }
static void* t1(void *unused) { WAIT1(sem0); puts("hello from t1"); POST1(sem1); return 0; }
static void* t2(void *unused) { WAIT1(sem1); puts("hello from t2"); return 0; }
int main(void)
{
key_t sem0_k, sem1_k;
sem0_k = ftok("/tmp", '0');
sem1_k = ftok("/tmp", '1');
sem0 = semget(sem0_k, 1, (IPC_CREAT|IPC_EXCL|0666));
sem1 = semget(sem1_k, 1, (IPC_CREAT|IPC_EXCL|0666));
pthread_t tids[3];
pthread_create(tids+2, NULL, t2, NULL);
sleep(1);
pthread_create(tids+1, NULL, t1, NULL);
sleep(1);
pthread_create(tids+0, NULL, t0, NULL);
for(int i = 0; i < 3; i++)
pthread_join(tids[i], NULL);
semctl(sem0, 0, IPC_RMID, NULL);
semctl(sem1, 0, IPC_RMID, NULL);
return 0;
}我以反向顺序运行线程,在t0和t1之间等待1秒,t1和t2显示信号量,完成将线程从t0排序到t2的工作。
发布于 2017-04-21 18:37:00
@PSkocik,基于您的回答,我修改了我的代码,使用了一组两个信号量。以下是代码:
#include <stdio.h>
#include <unistd.h>
#include <pthread.h>
#include <sys/types.h>
#include <sys/ipc.h>
#include <sys/sem.h>
#include <errno.h>
int sem_id;
struct sembuf sops;
void thread_1(void)
{
/*Wait on Set1 of Semaphore*/
sops.sem_num = 1;
sops.sem_op = -1;
sops.sem_flg = 0;
if(semop(sem_id, &sops, 1) < 0)
perror("Semop Wait In thread 3");
else
printf("Hello From thread 1\n");
}
void thread_2(void)
{
/*Wait on Set0 of Semaphore*/
sops.sem_num = 0;
sops.sem_op = -1;
sops.sem_flg = 0;
if(semop(sem_id, &sops, 1) < 0)
perror("Semop Wait In thread 2");
else
printf("Hello from thread 2\n");
/*Post on Set1 of Semaphore*/
sops.sem_num = 1;
sops.sem_op = 1;
sops.sem_flg = 0;
if(semop(sem_id, &sops, 1) < 0)
perror("Semop Post In thread 2");
}
void thread_3(void)
{
printf("Hello from thread 3\n");
/*Post operation on Set0 of semaphore*/
sops.sem_num = 0;
sops.sem_op = 1;
sops.sem_flg = 0;
if(semop(sem_id, &sops, 1) < 0)
perror("Semop In thread 3");
else
{ ; }
}
int main(void)
{
void (*funct[]) = {thread_1, thread_2, thread_3};
key_t semkey;
char i;
union semun {
int val; /* Value for SETVAL */
struct semid_ds *buf; /* Buffer for IPC_STAT, IPC_SET */
unsigned short *array; /* Array for GETALL, SETALL */
struct seminfo *__buf; /* Buffer for IPC_INFO
(Linux-specific) */
}arg;
pthread_t thread_id[3];
semkey = ftok("/tmp", 'a');
if(semkey < 0)
perror("Cannot Create Semaphore Key");
else
{
sem_id = semget(semkey, 2, (IPC_CREAT|IPC_EXCL|0666));
if(sem_id < 0)
perror("Cannot create semaphore\n");
else
{
/*arg.val = 3;
if (semctl(sem_id, 0, SETVAL, arg) == -1) {
perror("semctl");
exit(1);
}*/
}
}
for(i = 0; i < 3; i++)
{
if(pthread_create(&thread_id[i], NULL, funct[i], NULL) < 0)
perror("Cannot Create thread\n");
}
for(i = 0; i < 3; i++)
pthread_join(thread_id[i], NULL);
if(semctl(sem_id, 0, IPC_RMID, NULL) == -1)
perror("semctl");
return 0;
}顺便谢谢你的解释。
https://stackoverflow.com/questions/43548740
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