JPA 2.1 @SqlResultSetMapping将内部类绑定到to类

Question

是否有可能将内部类映射到targetclass，如果可能，它是如何完成的？我对这个@SqlResultSetMapping功能很陌生：

@SqlResultSetMapping(
        name = "EventSurveysMapping",
        classes = {
                @ConstructorResult(
                        targetClass = Survey.class,
                        columns = {
                                @ColumnResult(name = "surveyid", type = Long.class),
                        })
        })

因此，targetClass Survey.class有：

public class Survey {
    private Long surveyid;
    private List<SurveyQuestion> surveyquestions;
// constructor with mapped fields
}

如何映射List<SurveyQuestion>字段？

SurveyQuestion：

public class SurveyQuestion {
    private Long surveyquestionid;
    private String surveyquestion;
    private List<String> surveyanswers;
}

而且非常相似。我将如何映射List<String>？

在尝试映射到List.class时，我得到了一个异常：

@SqlResultSetMapping(
        name = "EventPollsMapping",
        classes = {
                @ConstructorResult(
                        targetClass = Poll.class,
                        columns = {
                                @ColumnResult(name="pollid", type = Long.class),
                                @ColumnResult(name="questionid", type = Long.class),
                                @ColumnResult(name="pollquestion", type = String.class),
                                @ColumnResult(name="pollanswers", type = List.class) // this mapping is the cause of the exception
                        })
        })

例外：

org.eclipse.persistence.exceptions.ConversionException异常描述:它是主ID的对象，它是类java.lang.String的唯一ID，无法转换为接口java.util.List

民意调查：

@XmlRootElement
@XmlType (propOrder={"pollid",
"pollquestionid",
"pollquestion",
"pollanswers"
})
public class Poll {
    private Long pollid;
    private Long pollquestionid;
    private String pollquestion;
    private List<String> pollanswers;


    public Poll(){}

    public Poll(Long pollid, Long pollquestionid, String pollquestion, List<String> pollanswers) {
        super();
        this.pollid = pollid;
        this.pollquestionid = pollquestionid;
        this.pollquestion = pollquestion;
        this.pollanswers = pollanswers;
    }

// setters & getters 
}

Answer 1

根据我的经验，当我必须绘制一个集合的地图时，最后我做了这样的事情：

@OneToMany
private Set<SurveyQuestion> surveyanswers;

如果您使用的是支持基本类型集合的JPA提供程序的扩展，那么所有这些都会发生。(例如，Hibernate有@CollectionOfElements注释)。