从另一个列表中筛选列表

Question

我有两个列表(即查询集和列表)：

filter_perceptions：

<QuerySet [<Perception: Perception #0000001>, <Perception: Perception #0000009>, <Perception: Perception #0000017>, <Perception: Perception #0000018>]>

还有另一份名单

results：

[{u'object': <Perception: Perception #0000018>, u'cols': <generator object items_for_result at 0x7f9264c56780>}, {u'object': <Perception: Perception #0000017>, u'cols': <generator object items_for_result at 0x7f9264c562d0>}, {u'object': <Perception: Perception #0000016>, u'cols': <generator object items_for_result at 0x7f926532bc30>}, {u'object': <Perception: Perception #0000015>, u'cols': <generator object items_for_result at 0x7f9264c178c0>}, {u'object': <Perception: Perception #0000014>, u'cols': <generator object items_for_result at 0x7f9264c17f50>}, {u'object': <Perception: Perception #0000013>, u'cols': <generator object items_for_result at 0x7f9264c17fa0>}, {u'object': <Perception: Perception #0000012>, u'cols': <generator object items_for_result at 0x7f9264c17960>}, {u'object': <Perception: Perception #0000011>, u'cols': <generator object items_for_result at 0x7f92643a3050>}, {u'object': <Perception: Perception #0000010>, u'cols': <generator object items_for_result at 0x7f92643a30a0>}, {u'object': <Perception: Perception #0000009>, u'cols': <generator object items_for_result at 0x7f92643a30f0>}, {u'object': <Perception: Perception #0000008>, u'cols': <generator object items_for_result at 0x7f92643a3140>}, {u'object': <Perception: Perception #0000007>, u'cols': <generator object items_for_result at 0x7f92643a3190>}, {u'object': <Perception: Perception #0000006>, u'cols': <generator object items_for_result at 0x7f92643a31e0>}, {u'object': <Perception: Perception #0000005>, u'cols': <generator object items_for_result at 0x7f92643a3230>}, {u'object': <Perception: Perception #0000004>, u'cols': <generator object items_for_result at 0x7f92643a3280>}, {u'object': <Perception: Perception #0000003>, u'cols': <generator object items_for_result at 0x7f92643a32d0>}, {u'object': <Perception: Perception #0000002>, u'cols': <generator object items_for_result at 0x7f92643a3320>}, {u'object': <Perception: Perception #0000001>, u'cols': <generator object items_for_result at 0x7f92643a3370>}]

我想用最后两个列表创建一个新列表。事实上，我想对results进行过滤，以便保持与filter_perceptions的看法一致的列表。谁能想到我们怎么能聪明地做这样的事呢？

下面是剩余列表的一个示例

[{u'object': <Perception: Perception #0000018>, u'cols': <generator object items_for_result at 0x7f9264c56780>}, {u'object': <Perception: Perception #0000017>, {u'object': <Perception: Perception #0000009>, {u'object': <Perception: Perception #0000001>, u'cols': <generator object items_for_result at 0x7f92643a3370>}]

谢谢!

P.S.如果问题不清楚请告诉我。

Answer 1

试一试

[r for r in results if r['object'] in filter_perceptions]