数据快照转换失败

Question

我目前正在使用firebase存储我的所有信息，我使用firebase身份验证进行了用户注册，并将该用户扩展到数据库，重用在身份验证中创建的id，现在我需要获取所有用户，并将他的手机与插入的电话进行比较，并在号码匹配时检索该特定用户，因此我这样做了：

码

FirebaseDatabase.getInstance().getReference().child("Users")
                .addListenerForSingleValueEvent(new ValueEventListener() {
                    @Override
                    public void onDataChange(DataSnapshot dataSnapshot) {
                        for (DataSnapshot snapshot : dataSnapshot.getChildren()) {
                            Log.d("snapshot", String.valueOf(snapshot));
                            Log.d("snap",String.valueOf(snapshot.getValue(User.class)));
                            User user = snapshot.getValue(User.class);
                            if(number.equals(String.valueOf(user.getPhone()))){
                                userFriend = user;
                            }

                        }

                        if(userFriend == null){
                            //to do snackbar
                        }
                    }

用户类

public class User {

    private String id;
    private String username;
    private int age = -1;
    private String phone;
    private int gamesPlayed = 0;
    private ArrayList<User> friends = new ArrayList<User>();

    // CONSTRUCTOR
    public User() {

    }

    public User(String username) {
        this.username = username;
    }

    // GETTERS & SETTERS
    public String getUsername() { return username; }
    public void setUsername(String username) { this.username = username; }

    public User(String id, String username, int age, String phone, int gamesPlayed, ArrayList<User> users) {
        this.id = id;
        this.username = username;
        this.age = age;
        this.phone = phone;
        this.gamesPlayed = gamesPlayed;
        this.friends = users;
    }

    public int getAge() { return age; }
    public void setAge(int age) { this.age = age; }

我的数据库结构：

​

​

，下面是我在堆栈跟踪中得到的信息：

04-20 16:06:04.070 30972-30972/com.esmad.pdm.friendlymanager E/AndroidRuntime: FATAL EXCEPTION: main
                                                                               Process: com.esmad.pdm.friendlymanager, PID: 30972
   com.google.firebase.database.DatabaseException: Failed to convert value of type java.lang.Long to String
       at com.google.android.gms.internal.zzbtg.zzaF(Unknown Source)
       at com.google.android.gms.internal.zzbtg.zzb(Unknown Source)
       at com.google.android.gms.internal.zzbtg.zza(Unknown Source)
       at com.google.android.gms.internal.zzbtg.zzb(Unknown Source)
       at com.google.android.gms.internal.zzbtg$zza.zze(Unknown Source)
       at com.google.android.gms.internal.zzbtg$zza.zzaH(Unknown Source)
       at com.google.android.gms.internal.zzbtg.zze(Unknown Source)
       at com.google.android.gms.internal.zzbtg.zzb(Unknown Source)
       at com.google.android.gms.internal.zzbtg.zza(Unknown Source)
       at com.google.firebase.database.DataSnapshot.getValue(Unknown Source)
       at com.esmad.pdm.friendlymanager.Friends$1.onDataChange(Friends.java:61)
       at com.google.firebase.database.Query$1.onDataChange(Unknown Source)
       at com.google.android.gms.internal.zzbpx.zza(Unknown Source)
       at com.google.android.gms.internal.zzbqx.zzZS(Unknown Source)
       at com.google.android.gms.internal.zzbra$1.run(Unknown Source)
       at android.os.Handler.handleCallback(Handler.java:751)
       at android.os.Handler.dispatchMessage(Handler.java:95)
       at android.os.Looper.loop(Looper.java:154)
       at android.app.ActivityThread.main(ActivityThread.java:6119)
       at java.lang.reflect.Method.invoke(Native Method)
       at com.android.internal.os.ZygoteInit$MethodAndArgsCaller.run(ZygoteInit.java:886)
       at com.android.internal.os.ZygoteInit.main

(ZygoteInit.java:776)

此错误与以下一行相关：User user = snapshot.getValue(User.class);

我怀疑这与我构建用户模型的方式和我检索的数据有关，有些东西是不兼容的。我的模型gamesPlayed和年龄有2个int，但是当我将用户传递给快照时，我不知道如何传递cas 2特定的值，这样我就可以传递它们了，我需要重新定义用户实例吗？或者一切都好，请帮我弄糊涂:/‘

Answer 1

在您的用户类中，您的电话字段必须是Long类型。