下表有两个字段:
create table tbl_jtest
(
cola int,
colb varchar(10)
);插入一些记录:
insert into tbl_jtest values(1,'a');
insert into tbl_jtest values(2,'b');
insert into tbl_jtest values(3,'c');
insert into tbl_jtest values(4,'d');函数
CREATE OR REPLACE FUNCTION ufn_jtest1(pcola int)
RETURNS json AS
$$
BEGIN
IF pcola = 1
THEN
RETURN QUERY SELECT to_json(a.cola) FROM tbl_jtest a;
ELSE
RETURN QUERY SELECT to_json(a.colb) FROM tbl_jtest a;
END IF;
END;
$$ LANGUAGE plpgsql;错误详细信息
错误:不能在非SETOF函数行7:返回查询从to_json a中选择tbl_jtest (a.cola);^
我试过以下几种方法:
Try 1
PERFORM to_json(a.cola) FROM tbl_jtest a;Try 2
RETURN QUERY PERFORM to_json(a.cola) FROM tbl_jtest a;发布于 2017-04-20 08:05:42
还是你在找这样的东西?
create table tbl_jtest
(
cola int,
colb varchar(10),
colc varchar(10)
);
insert into tbl_jtest values(1,'a','e');
insert into tbl_jtest values(2,'b','f');
insert into tbl_jtest values(3,'c','g');
insert into tbl_jtest values(4,'d','h');
SELECT * FROM tbl_jtest;
CREATE OR REPLACE FUNCTION ufn_jtest1(pcola int)
RETURNS table (j json) AS
$$
BEGIN
IF pcola = 1
THEN
RETURN QUERY SELECT row_to_json(a) FROM (SELECT cola, colb FROM tbl_jtest) a;
ELSE
RETURN QUERY SELECT to_json(a) FROM (SELECT colb, colc FROM tbl_jtest) a;
END IF;
END;
$$ LANGUAGE plpgsql;测试1
SELECT ufn_jtest1(1);产出1
ufn_jtest1
1 {"cola":1,"colb":"a"}
2 {"cola":2,"colb":"b"}
3 {"cola":3,"colb":"c"}
4 {"cola":4,"colb":"d"}Test2
SELECT ufn_jtest1(2);Output2 ufn_jtest1
1 {"colb":"a","colc":"e"}
2 {"colb":"b","colc":"f"}
3 {"colb":"c","colc":"g"}
4 {"colb":"d","colc":"h"}发布于 2017-04-20 07:47:42
你想要这样吗?
CREATE OR REPLACE FUNCTION ufn_jtest2(pcola int)
RETURNS table (j json) AS
$$
BEGIN
IF pcola = 1
THEN
RETURN QUERY SELECT to_json(a.cola) FROM tbl_jtest a;
ELSE
RETURN QUERY SELECT to_json(a.colb) FROM tbl_jtest a;
END IF;
END;
$$ LANGUAGE plpgsql;https://stackoverflow.com/questions/43512831
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