BeautifulSoup -获取用逗号分隔的所有<a>标记

Question

为了获取网站中的所有标签，我有一段代码：

results=[]

all_links = soup.find_all('article')
        for link in all_links:
            print link.find('div', class_="cb-category cb-byline-element")

通过这种方式，我可以得到以以下方式显示的数据(使用','，分离<a>标记)：

<div class="cb-category cb-byline-element"><i class="fa fa-folder-o"></i> <a href="http://ridethetempo.com/category/canadian/" title="View all posts in Canadian">Canadian</a>,  <a href="http://ridethetempo.com/category/music/garage-rock/" title="View all posts in Garage">Garage</a>,  <a href="http://ridethetempo.com/category/listen-2/" title="View all posts in Listen">Listen</a>,  <a href="http://ridethetempo.com/category/music/" title="View all posts in Music">Music</a>,  <a href="http://ridethetempo.com/category/music/psychedelic/" title="View all posts in Psychedelic">Psychedelic</a>,  <a href="http://ridethetempo.com/category/under-2000/" title="View all posts in Under 2000">Under 2000</a></div>

但是，如果我这样做的话：

 results.append(link.find('div', class_="cb-category cb-byline-element"))
 for link in results:
     link.find('a', href=True)['href']

我只为每个<div>块获得第一个<div>，如下所示：

http://ridethetempo.com/category/canadian/

如何递归地检索所有<a>标记，最后得到这个结果？

http://ridethetempo.com/category/canadian/ 
http://ridethetempo.com/category/music/garage-rock/
http://ridethetempo.com/category/listen-2/
http://ridethetempo.com/category/music/ 
http://ridethetempo.com/category/music/psychedelic/
http://ridethetempo.com/category/under-2000/

Answer 1

for link in soup.find_all('a'):
    print(link.get('href'))

将打印所有“a”标记元素。