使AppVeyor允许使用Python失败

Question

我一直在利用AppVeyor来尝试用我的GitHub项目来设置它。我的AppVeyor构建可以定位为这里。

由于我正在使用Python，而且版本太多，我希望能够允许3.2、3.3和3.4失败。我可以在Travis-CI上做得很好，输入：

python:
    - "2.7"
    - "3.2" # End of life.
    - "3.3"
    - "3.4"
    - "3.5"
    - "3.6"
    - "nightly"

matrix:
  allow_failures:
    - python: "3.2"
    - python: "3.3"
    - python: "3.4"
    - python: "nightly"

然而，在AppVeyor中，我做了以下工作：

environment:
  matrix:
      # 32-bit Python.
    - PYTHON: "C:\\Python27"
      PYTHON_VERSION: "2.7.x"
      PYTHON_ARCH: "32"
    - PYTHON: "C:\\Python32"
      PYTHON_VERSION: "3.2.x"
      PYTHON_ARCH: "32"
    - PYTHON: "C:\\Python33"
      PYTHON_VERSION: "3.3.x"
      PYTHON_ARCH: "32"
    - PYTHON: "C:\\Python34"
      PYTHON_VERSION: "3.4.x"
      PYTHON_ARCH: "32"
    - PYTHON: "C:\\Python35"
      PYTHON_VERISON: "3.5.x"
      PYTHON_ARCH: "32"
    - PYTHON: "C:\\Python36"
      PYTHON_VERISON: "3.6.x"
      PYTHON_ARCH: "32"

      # 64-bit Python.
    - PYTHON: "C:\\Python27-x64"
      PYTHON_VERSION: "2.7.x"
      PYTHON_ARCH: "64"
    - PYTHON: "C:\\Python32-x64"
      PYTHON_VERSION: "3.2.x"
      PYTHON_ARCH: "64"
    - PYTHON: "C:\\Python33-x64"
      PYTHON_VERSION: "3.3.x"
      PYTHON_ARCH: "64"
    - PYTHON: "C:\\Python34-x64"
      PYTHON_VERSION: "3.4.x"
      PYTHON_ARCH: "64"
    - PYTHON: "C:\\Python35-x64"
      PYTHON_VERISON: "3.5.x"
      PYTHON_ARCH: "64"
    - PYTHON: "C:\\Python36-x64"
      PYTHON_VERISON: "3.6.x"
      PYTHON_ARCH: "64"

matrix:
    allow_failures:
        - platform: x86
          PYTHON: "C:\\Python32"
          PYTHON_VERSION: "3.2.x"
        - platform: x86
          PYTHON: "C:\\Python33"
          PYTHON_VERSION: "3.3.x"
        - platform: x86
          PYTHON: "C:\\Python34"
          PYTHON_VERSION: "3.4.x"
        - platform: x64
          PYTHON: "C:\\Python32-x64"
          PYTHON_VERSION: "3.2.x"
        - platform: x64
          PYTHON: "C:\\Python33-x64"
          PYTHON_VERSION: "3.3.x"
        - platform: x64
          PYTHON: "C:\\Python34-x64"
          PYTHON_VERSION: "3.4.x"

正如您在下面看到的，在我最近的构建中，仍然是，无法检测到3.3x64位错误的允许性。

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现在，我已经了解了如何正确格式化我的允许失败，却找不到Python的任何内容。然而，我确实找到了一个GitHub项目，它隐藏在评论中，所以我只是假设遵循这种格式：

#matrix:
#  allow_failures:
#    - platform: x86
#      PYTHON: "C:\\Python27"
#      PYTHON_VERSION: "2.7"

因此，我的问题是，如何使AppVeyor允许我同时失败x86和x64位架构的特定Python构建？

Answer 1

某些特定矩阵配置的允许失败并不意味着此配置的作业将始终是绿色的。这意味着，即使这个工作失败了，它也不会影响整个构建的状态。

对于Visual解决方案/项目，platform主要是有意义的，对于您的情况，类似这样的东西应该可以正常工作：

matrix:
    allow_failures:
      - PYTHON: "C:\\Python32"
        PYTHON_VERSION: "3.2.x"
        PYTHON_ARCH: "32"
      - PYTHON: "C:\\Python33"
        PYTHON_VERSION: "3.3.x"
        PYTHON_ARCH: "32"
      - PYTHON: "C:\\Python34"
        PYTHON_VERSION: "3.4.x"
        PYTHON_ARCH: "32"
      - PYTHON: "C:\\Python32-x64"
        PYTHON_VERSION: "3.2.x"
        PYTHON_ARCH: "64"
      - PYTHON: "C:\\Python33-x64"
        PYTHON_VERSION: "3.3.x"
        PYTHON_ARCH: "64"  
      - PYTHON: "C:\\Python34-x64"
        PYTHON_VERSION: "3.4.x"
        PYTHON_ARCH: "64"