从for循环中得到值？

Question

我想得到所有的数值并打印到(.)但我不能那样做。你能帮帮我吗？

public static void main(String[] args) {
    // TODO Auto-generated method stub
    Scanner keyboard = new Scanner(System.in);
    int operands,num;
    int q=1;
    int a=0;

    do 
    {
        System.out.println("Enter the number of operands (in range 2-10):");
        operands=keyboard.nextInt();            
    } while ((operands<2) || (operands>10));

    for (int number=1; number<=operands; number++)
    {
        System.out.println("Enter number "+number+":");
        num=keyboard.nextInt();
        q=q*num;
    }

    System.out.print("Multiplication of numbers "+(.......)+" is: "+q);

Answer 1

使用在循环之前声明的额外字符串变量：

String numbers=" ";

并在循环体中添加：

numbers += num+" ";

然后在(.)处打印出该字符串。

Answer 2

我喜欢FranzKnut的答案，但是如果性能是个问题，即使不是，那么请考虑使用字符串生成器。

在循环使用之前

StringBuilder sb = new StringBuilder("my numbers are: ");

在循环中添加以下代码。

sb.append(num);

然后，在循环的末尾，您有如下所示

System.out.println(sb.toString());

Answer 3

只需在程序中添加一个字符串，并与新添加的数字连接。最后，将字符串打印到必须打印的位置。

public static void main(String[] args) {
    // TODO Auto-generated method stub
    Scanner keyboard = new Scanner(System.in);
    int operands, num;
    int q = 1;
    int a = 0;
    String s = " ";
    do {
        System.out.println("Enter the number of operands (in range 2-10):");
        operands = keyboard.nextInt();
    } while ((operands < 2) || (operands > 10));


    for (int number = 0; number <= operands - 1; number++) {
        System.out.println("Enter number " + number + ":");
        num = keyboard.nextInt();
        s = s + num;
        q = q * num;
    }



    System.out.print("Multiplication of" + s + " numbers is: " + q);
}