Spring : URL模式

Question

这是我的web.xml

<servlet>
      <servlet-name>Learn</servlet-name>
      <servlet-class>
         org.springframework.web.servlet.DispatcherServlet
      </servlet-class>
      <load-on-startup>1</load-on-startup>
   </servlet>

   <servlet-mapping>
      <servlet-name>Learn</servlet-name>
      <url-pattern>/learn/*</url-pattern>
   </servlet-mapping>

如果我更改这段代码

<url-pattern>/learn/*</url-pattern>

至

<url-pattern>/learn/abc/</url-pattern>

我可以按我的控制器代码，它是

@Controller
@RequestMapping(value = "/learn")
public class ControllerClass
{
    @RequestMapping(value = "/", method = RequestMethod.GET)
    public String callRequest(ModelMap model)
    {
        return "index";
    }

    @RequestMapping(value = "/abc/", method = RequestMethod.GET)
    public String personController(ModelMap model)
    {
        return "welcome";
    }
}

但我也想点击第一个方法，否则我会添加更多的方法，这是我无法实现的。

/learn/abc/

在url地图上。

所以请帮帮我

pom.xml

<dependencies>

        <dependency>
            <groupId>javax.servlet</groupId>
            <artifactId>servlet-api</artifactId>
            <version>2.5</version>
        </dependency>

        <dependency>
            <groupId>junit</groupId>
            <artifactId>junit</artifactId>
            <version>3.8.1</version>
            <scope>test</scope>
        </dependency>

        <!-- spring-context which provides core functionality -->
        <dependency>
            <groupId>org.springframework</groupId>
            <artifactId>spring-context</artifactId>
            <version>4.1.6.RELEASE</version>
        </dependency>

        <!-- The spring-aop module provides an AOP Alliance-compliant aspect-oriented 
            programming implementation allowing you to define -->
        <dependency>
            <groupId>org.springframework</groupId>
            <artifactId>spring-aop</artifactId>
            <version>4.1.6.RELEASE</version>
        </dependency>

        <!-- The spring-webmvc module (also known as the Web-Servlet module) contains 
            Spring’s model-view-controller (MVC) and REST Web Services implementation 
            for web applications -->
        <dependency>
            <groupId>org.springframework</groupId>
            <artifactId>spring-webmvc</artifactId>
            <version>4.1.6.RELEASE</version>
        </dependency>

        <!-- The spring-web module provides basic web-oriented integration features 
            such as multipart file upload functionality and the initialization of the 
            IoC container using Servlet listeners and a web-oriented application context -->
        <dependency>
            <groupId>org.springframework</groupId>
            <artifactId>spring-web</artifactId>
            <version>4.1.6.RELEASE</version>
        </dependency>
    </dependencies>

如果我错过了任何依赖，请告诉我

Answer 1

使用这个url模式的<url-pattern>/learn/*</url-pattern>配置，要命中您的方法，url路径将是：/学习/学习。

web.xml上的url模式像spring servlet的basepath一样工作。因此，一个很好的选择是将url模式更改为/*，如下所示：

<url-pattern>/*</url-pattern>

或者，如果您希望使用basepath，请将url模式更改为: /basepath/*

要命中您的方法，需要使用路径url：/basepath/learn