/：'str‘和'int’的不支持的操作数类型

Question

我是初学者，很抱歉这很明显或者很奇怪。我也很抱歉，如果这已经得到了回答，我只是找不到真正有效的东西。

我正试着制作一个程序来加密和解密文本文件。

我的想法是将字符加密成数字形式，并将它们相乘为加密，当然也可以作为解密。

加密部分工作得很好，但是当运行解密代码时，我会得到一个

不支持/的操作数类型：'str‘和'int’。

我试过浮点和整数，但它们不起作用。

加密代码：

import binascii

#ENCRYPTION ALGORITHM
algorithm = 2

#ASCII ----> NUMBERS
raw = raw_input("Enter text to encrypt:")
one = binascii.hexlify(raw)
two = binascii.hexlify(one)

#UNENCRYPTED HEX
unencrypted = int(two)

#ENCRYPT HEX
encrypted =  unencrypted * algorithm

#PRINTS ENCRYPTED TEXT
print "%.9f" % encrypted

解密码：

import time
import binascii

incorrectpasswords = 0
password=("mypass")
originpassword = password
x = 1
algorithm = 2

while x==1:
    passwordattempt =raw_input("Enter Password:")
    if passwordattempt == password:
        print("Correct")
        x = 2

    if passwordattempt!= password:
        print("Incorrect")
        incorrectpasswords = incorrectpasswords + 1
    if incorrectpasswords > 2:
        if x == 1:
            password = (generatedpassword)
            print("Too many wrong attempts, please try again in one minute.")
            time.sleep(60)
            password=originpassword


encrypted = float(input("Enter text to unencrypt:"))
formatted = "%.9f" % encrypted
formatted2 = formatted
one = formatted2 / algorithm
print ("%.9f" % one)
two = binascii.unhexlify(one)
unencrypted = binascii.unhexlify(two)
print(unencrypted)

而且，python 2.7中的binascii在python 3中不适用于我。

Answer 1

您不应该尝试将格式化的字符串除以数字。

algorithm = 2

encrypted = float(input("Enter text to unencrypt:"))
one = encrypted / algorithm
print("%.9f" % one)