我有一个情况,我不知道这是否有可能做到。
我有两个桌子我需要加入和使用计数。
表1= "EPM_ProjectUserview“
[ProjectUID], [ProjectName], [EnterpriseProjectTypeUID](used as a filter)Table2 = "EpmTask_UserView“
[ProjectUID],[Task_Significance], [TaskPercentCompleted] then 3 count fields
[total Count], [Count 100% complete], Count <1005]这个会给我一张像这样的桌子
注意:有第一列不适合项目名称
|Apps|Overall% Comp| Totl Count|100% Compl|Not 100% Comp|Overall Health|接口的同一行为真。
总体%完成,总体健康来自总结任务。
(this is project server) ProjectUID是连接的一个关键字段。
因此,我有5个不同的查询,所有的工作,但,当然,我需要他们在一个表。
查询1-这是项目名称projectUID和EnterpriseprojecttypeUID
SELECT [ProjectName]
,[ProjectUID]
,[EnterpriseProjectTypeUID]
FROM [dbo].[MSP_EpmProject_UserView]
where [projectUID] not like '0000CF75-FB12-4FFC-A404-AEC4F3258A9C'
And
[EnterpriseProjectTypeUID] like '76194144-3CDB-E611-9419-00215A9259E8'
order by [ProjectName] 查询2给出了每种类型的总数。
SELECT p.[ProjectName]
,T.[Task_Significance]
-- ,T.[TaskPercentCompleted]
,count (*) as [Total Count]
FROM [psmado].[dbo].[MSP_EpmProject_UserView] as P
join [PSMADO].[dbo].[MSP_EpmTask_UserView] as T
On T.[projectUID] = P.[projectUID]
where
([Task_Significance] like 'App'
Or
[Task_Significance] like 'Interface')
Group by [ProjectName], [Task_Significance]查询3-下一个查询给我100%完整的列
SELECT p.[ProjectName]
,T.[Task_Significance]
-- ,T.[TaskPercentCompleted]
,count (*) as [Count]
FROM [psmado].[dbo].[MSP_EpmProject_UserView] as P
join [PSMADO].[dbo].[MSP_EpmTask_UserView] as T
On T.[projectUID] = P.[projectUID]
where T.[TaskPercentCompleted] >= 100
and
([Task_Significance] like 'App'
Or
[Task_Significance] like 'Interface')
Group by [ProjectName], [Task_Significance]查询4-下一个查询给出的是未完成100%的查询。
SELECT p.[ProjectName]
,T.[Task_Significance]
-- ,T.[TaskPercentCompleted]
,count (*) as [Count]
FROM [psmado].[dbo].[MSP_EpmProject_UserView] as P
join [PSMADO].[dbo].[MSP_EpmTask_UserView] as T
On T.[projectUID] = P.[projectUID]
where T.[TaskPercentCompleted] < 100
and
([Task_Significance] like 'App'
Or
[Task_Significance] like 'Interface')
Group by [ProjectName], [Task_Significance]查询5最后,整个任务运行状况和%完成来自表中的不同行
SELECT [dbo].[MSP_EpmProject_UserView].[ProjectName]
,[dbo].[MSP_EpmTask_UserView].[ProjectUID]
,[dbo].[MSP_EpmTask_UserView].[TaskName] as [Name]
,[dbo].[MSP_EpmTask_UserView].[TaskPercentCompleted] as [% Complete]
,[dbo].[MSP_EpmTask_UserView].[Task Health] as [Health]
,[dbo].[MSP_EpmTask_UserView].[Task_Significance]
,[dbo].[MSP_EpmTask_UserView].[TaskOutlineNumber]
FROM [dbo].[MSP_EpmTask_UserView]
inner join [PSMADO].[dbo].[MSP_EpmProject_UserView]
on [dbo].[MSP_EpmTask_UserView].[projectuid] = [PSMADO].[dbo].[MSP_EpmProject_UserView].[ProjectUID]
where [dbo].[MSP_EpmTask_UserView].[projectUID] not like '0000CF75-FB12-4FFC-A404-AEC4F3258A9C' -- the timesheet project null
and [Task_Significance] like 'App Summary'
or [Task_Significance] like 'Interface Summary'
order by [ProjectName], [TaskOutlineNumber]这些是否可以放在一张桌子上(工会不是为我工作的),如果是的话,怎么做呢?
谢谢你的帮助
杰克斯的回答非常接近。这就是我需要的:

这就是我要得到的。你可以看到,它只是重复了每一节。(我砍掉了一部分,但有36排。)

发布于 2017-04-06 02:18:19
对你来说最好也是最简单的方法就是..。使用公共表表达式..。它不允许我将所有代码粘贴到这个表达式中,但是您可以直接使用以下语法来完成它。
使用t1 as (在这些括号中粘贴第一个查询完整)、t2 as (在这些括号中粘贴第二个查询完整)、t3 as (在这些括号中粘贴第三个查询完整)、t4 as (在这些括号中粘贴第4个查询完整)、t5 as (在这些括号中粘贴第5个查询完整)。
现在,在完成之后,编写一个查询并提取您想要的任何数据。例如
从t1、t2、t3、t4、t5中选择t1.abc、t2.abc、t3.xyz、t4.lmn、t5.xyz
希望这能有所帮助。
发布于 2017-04-06 19:13:35
谢谢大家的意见和帮助。这是一个如此伟大的社区!所以我最终走向了一个不同的方向,因为杰克斯的想法使我走上了一条道路。
SELECT pr.[ProjectName]
,T.[Task_Significance]
, sum (case when T.[TaskPercentCompleted] is not null and T.[Task_Significance] ='App' Or T.[TaskPercentCompleted] is not null and T.[Task_Significance] = 'Interface' then 1 else 0 end) as [Total]
, sum (case when T.[TaskPercentCompleted] < 30 and T.[Task_Significance] ='App' Or T.[TaskPercentCompleted] < 30 and T.[Task_Significance] = 'Interface' then 1 else 0 end) as [Incomplete]
, sum (case when T.[TaskPercentCompleted] >= 30 and T.[Task_Significance] ='App' Or T.[TaskPercentCompleted] >= 30 and T.[Task_Significance] = 'Interface' then 1 else 0 end) as [Complete]
FROM [psmado].[dbo].[MSP_EpmProject_UserView] as Pr
join [PSMADO].[dbo].[MSP_EpmTask_UserView] as T
On T.[projectUID] = Pr.[projectUID]
Where
T.[Task_Significance] like 'App'
Or
T.[Task_Significance] like 'Interface'
Group by pr.[ProjectName], T.[Task_Significance]https://stackoverflow.com/questions/43241463
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