PHP MySQL事务捕获错误

Question

我已经找了两天了，还没找到答案。假设我在PHP中有下面的代码：

$mysqli->begin_transaction();
mysqli_query($mysqli, "DELETE FROM Test WHERE ID=1");
mysqli_query($mysqli, "DELETE FROM TEST WHEREE ID=2"); <-- THIS ONE WILL FAIL BECAUSE OF TYPO
mysqli_query($mysqli, "DELETE FROM Test WHERE ID=3");
if ($mysqli->commit()) {
    //SUCCESS
    }
else {
    //Failed        
    $mysqli->rollback();
    }

我无法检查事务中的查询是否全部成功，因为当我执行这些查询时，提交函数总是返回true。

如何检查事务中的所有查询是否成功？

Answer 1

这样做的共同方法是：

$mysqli->begin_transaction();
try {
    mysqli_query($mysqli, "DELETE FROM Test WHERE ID=1");
    mysqli_query($mysqli, "DELETE FROM TEST WHEREE ID=2"); <-- THIS ONE WILL FAIL BECAUSE OF TYPO
    mysqli_query($mysqli, "DELETE FROM Test WHERE ID=3");
    $mysqli->commit();
} catch (\Exception $e) {
    // this will show statement with error
    echo $e->getMessage();
    $mysqli->rollback();
    throw $e;
}

Answer 2

您可以使用mysqli_error捕获错误。

$startTrans = 'START TRANSACTION;';  // Starting a mysql transaction
mysqli_query($conn, $startTrans); 

$query = 'Insert into students (roll_no,name,class) VALUES (101,"mathew","fourth")';
$result = mysqli_query($conn, $query);
if (mysqli_error($conn)) {
   // Rollback can be done here 
   mysqli_query($conn, "ROLLBACK;"); // All above queries will get rolled back
   die(mysqli_error($conn)); 
} else {
   mysqli_query($conn, "COMMIT;"); // changes will get saved to database
}