动态字符串的C++动态数组

Question

我知道如何在C++中创建一个动态字符串数组：

string* array = new string[10];

但是如何在C++中创建动态字符串的动态数组呢？我指的是一个包含string*对象的动态数组。以及如何初始化每个动态字符串？

Answer 1

我同意，如果您需要实现您所要求的，您可能应该重新考虑您的设计。但是，所询问的内容的语法与字符串数组完全相关：

string** sillyIdea = new string*[10];
//some access examples
sillyIdea[0]= new string;
*(sillyIdea[0]) = "hello";
(*(sillyIdea[0]))[0] = 'H'; 
 sillyIdea[1]= new string;

//statement below looks like a 2d array construct but it is not, 
//just shorthand for  
// *((sillyIdea[1]) + 0)
 sillyIdea[1][0] = "world"; 
//an array of pointers can usually be treated programtcally as a
//jaggedarray(asymtrical multi-dimensional array). In other words,
// your array of string pointers can be treated like an array of one
//element string arrays, making for a cleaner syntax, but worse code.

//in int main(int argc, char** argv), argv is one such example of a jagged array.

上面建议的字符串向量会产生较少的心痛。

Answer 2

(简单例子:)

#include <iostream>
using namespace std;

int main() {
    int n, m;
    cin>>n;
    cin>>m;
    string** array = new string*[n];

    for(int i = 0; i<n; i++)
    {
        array[i] = new string[m];
    }

    for(int i = 0; i<n; i++)
    for(int j = 0; j<n; j++)
    cin>>array[i][j];


    for(int i = 0; i<n; i++)
    for(int j = 0; j<n; j++)
    cout<<array[i][j]<<endl;



    return 0;
}