不知道为什么,但我一直把0作为输出参数.我运行了以下命令:
INSERT INTO users (first_name, last_name, email, image, date_of_registration)
VALUES ("xx", "xx", "xxx", null, sysdate());SELECT LAST_INSERT_ID();而且我得到了比我假设的PersistentConnections设置为true的好结果(!= 0)。还有其他可能导致这件事的秘密吗?
操作步骤
DROP PROCEDURE IF EXISTS partners.create_user;
CREATE DEFINER=`partnersmaster`@`%` PROCEDURE `create_user`(
IN p_first_name NVARCHAR(30),
IN p_last_name NVARCHAR(30),
IN p_email NVARCHAR(100),
IN p_image NVARCHAR(200),
IN p_date_of_registration TIMESTAMP,
OUT p_user_id INT
)
BEGIN
INSERT INTO users (first_name, last_name, email, image, date_of_registration)
VALUES (p_first_name, p_last_name, p_email, p_image, p_date_of_registration);
SET @p_user_id = LAST_INSERT_ID();
END;Java
conn = engine.getDal().getConnection();
st = conn.prepareCall("{call partners.create_user(?,?,?,?,?,?)}");
st.setString("p_first_name", user.getFirstName());
st.setString("p_last_name", user.getLastName());
st.setString("p_email", user.getEmail());
if(user.getImage() != null)
st.setString("p_image", user.getImage());
else
st.setNull("p_image", Types.NVARCHAR);
st.setTimestamp("p_date_of_registration", new Timestamp(System.currentTimeMillis()));
st.registerOutParameter("p_user_id", Types.INTEGER);
st.execute();
userId = st.getInt("p_user_id");发布于 2017-03-24 15:03:45
过程参数和会话变量- p_user_id与@p_user_id之间存在一个问题.在您的示例中,没有设置p_user_id。
用这种方式改变代码-
BEGIN
...
...
...
SET p_user_id = LAST_INSERT_ID();
END;https://stackoverflow.com/questions/43001596
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