当未对其签名时，ErrorException -试图获取非对象的属性(View: C：\xampp\.\how-solo.blde.php)

Question

祝大家今天好，我只想问一下拉勒维尔的情况，让我学习像我这样的学生。

在登录时，我可以访问以下页面：

Route::get('/posts/{id}', 'PostController@showById');

当我注销并尝试再次访问该页面时，我会看到提到的错误，我希望为来宾显示帖子，但如果他们被注销，则不允许撰写帖子。

下面是showById()：

public function showById($id)
{
    $post = Post::find($id);

    return view('show-solo', compact('post'));
}

还有显示-solo.blde.php

@extends('master')

@include('partials.nav-none')

@section('content')
    <div class="col-sm-8 blog-main">
        <div class="blog-post">

            @if ($flash = session('message'))
                <div class="alert alert-success flash-message" role="alert">
                    {{ $flash }}
                </div>
            @endif

            @if ( $post->user_id  == Auth::user()->id)
                <a href="/posts/{{ $post->id }}/delete">
                    <button class="btn-sm btn-warning post-btn" data-toggle="tooltip" data-placement="top" title="Delete Post"><i class="fa fa-times"></i></button>
                </a>
                <a href="/posts/{{ $post->id }}/edit">
                    <button class="btn-sm btn-primary post-btn" data-toggle="tooltip" data-placement="top" title="Edit Post"><i class="fa fa-pencil-square-o"></i></button>
                </a>
            @endif          

            <h2>Post number: {{ $post->id }}</h2>

            <h2 class="blog-post-title">
                <a class="title-link" href="/posts/{{ $post->id }}">{{ $post->title }}</a>
            </h2>

            <!-- {{ $post->created_at->toFormattedDateString() }} -->
            <p class="blog-post-meta">{{ $post->created_at->diffForHumans() }} by <a href="#">{{ $post->user->name }}</a></p>
            {{ $post->body }}

            <hr />

            @include('partials.error')

            @include('partials.post-comment')
        </div>
    </div>
@endsection

如果这有帮助，下面是我的路线：

Route::get('/', function () {
    return view('welcome');
});

Route::get('/posts', 'PostController@index')->name('home');

Route::get('/posts/create', 'PostController@showForm');

Route::get('/posts/{id}', 'PostController@showById');

Route::get('posts/{id}/edit', 'PostController@editPostForm');

Route::get('posts/{id}/delete', 'PostController@deletePost');

Route::post('/posts', 'PostController@store');

Route::post('/posts/{post}/comments', 'CommentController@store');

Route::get('posts/{id}/delete', 'CommentController@deleteComment');

Route::post('/save-post', 'PostController@savePost');



Auth::routes();

Route::get('/home', 'HomeController@index');



Route::get('/register-user', 'RegistrationController@create');

Route::post('/register-user', 'RegistrationController@store');





Route::get('/login-user', ['as' => '/login-user', 'uses' => 'SessionController@create']);

Route::post('/login-user', 'SessionController@store');

Route::get('/logout-user', 'SessionController@destroy');

我做错什么了吗？为什么即使我是客人，也不能访问/发布/{id}？“试图获取非对象的属性”意味着什么？

请告诉我是否应该在这里引用一些代码来帮助解决这个问题。

如有任何建议，将不胜感激。谢谢。

Answer 1

您将在下面的行中获得错误

@if ( $post->user_id  == Auth::user()->id)

在视野中。

您在这一行上得到错误的原因是您试图访问像Auth::user()->id这样的经过身份验证的用户的id。但是没有经过身份验证的用户。因此，Auth::user()调用返回null。您正在尝试访问id on null。

试着把它改成

@if ( $post->user_id  == @Auth::user()->id)

或

@if(Auth::user())
    @if ( $post->user_id  == Auth::user()->id)
    ...
    @endif
@endif