我有一个散点图Vizframe图表,其中我需要包括一个线性回归/趋势线。知道该怎么做吗?似乎这不是由电视“开箱即用”提供的东西吗?我找不到解决办法!
问题:
对于散点图Vizframe图上实现回归线的可行方法,有什么建议吗?
这是我的设置代码。当按下按钮时,散点图在对话框/模态中打开。
sap.ui.define([
'jquery.sap.global',
'vizConcept/controller/BaseController',
'sap/ui/model/json/JSONModel',
'vizConcept/model/viewControls',
'sap/m/Button',
'sap/m/Dialog',
],
function (jQuery, BaseController, JSONModel, viewControls, Button, Dialog) {
"use strict";
var controls;
var mainController = BaseController.extend("vizConcept.controller.Main", {
onInit: function(oEvent) {
// Access/expose the defined model(s) configured in the Component.js or Manifest.json within the controller.
this.getView().setModel(this.getOwnerComponent().getModel("products"), "products");
var oModel = this.getView().getModel("products");
this.getView().setModel(oModel);
var sUrl = "#" + this.getOwnerComponent().getRouter().getURL("page2");
$(function() {
var dataset = new sap.viz.ui5.data.FlattenedDataset({
dimensions : [
{
axis : 1,
name : 'Award Date',
value : "{AwdDate}"
}
],
measures : [
{
group: 1,
name : 'Award Date',
value : '{Hist}'
},
{
group: 2,
name : 'Current PPI',
value : '{Current}'
}
],
data : {
path : "/ProductCollection"
}
});
var scatterViz = new sap.viz.ui5.Scatter({
id : "idscatter",
width : "1000px",
height : "400px",
title : {
text : 'Pricing Tool Scatter Plot Example'
},
xAxis : {
title : {
visible : true
}
},
yAxis : {
title : {
visible : true
}
},
dataset : dataset
});
scatterViz.setModel(sap.ui.getCore().getModel());
scatterViz.setModel(oModel);
var dlg = new sap.m.Dialog({
id: 'vizModal',
title: 'Scatter Plot Example Viz',
width : "1800px",
height : "600px",
content : [scatterViz],
beginButton: new Button({
text: 'Close',
press: function () {
dlg.close();
}
})
});
(new sap.m.Button({
text: 'open',
type: 'Accept',
press: function() {
dlg.open();
scatterViz.invalidate();
}
})).placeAt('content');
});
},
onToPage2 : function () {
this.getOwnerComponent().getRouter().navTo("page2");
},
});
return mainController;
});编辑
这是在视频帧图上输出的“产品”模型。我在manifest.json中定义了产品模型,但是那里的连接很好:
产品模型
{
"ProductCollection": [
{
"Item": "1",
"AwdDate": "20160715",
"Hist": 171.9,
"Current": 183
},
{
"Item": "2",
"AwdDate": "20160701",
"Hist" : 144.3,
"Current": 158.6
},
{
"Item": "3",
"AwdDate": "20150701",
"Hist": 160,
"Current": 165
},
{
"Item": "1",
"AwdDate": "20160715",
"Hist": 201,
"Current": 167
},
{
"Item": "2",
"AwdDate": "20160801",
"Hist" : 175.3,
"Current": 178.2
},
{
"Item": "3",
"AwdDate": "20150721",
"Hist": 160,
"Current": 147
},
{
"Item": "1",
"AwdDate": "20160715",
"Hist": 175.9,
"Current": 185.2
},
{
"Item": "2",
"AwdDate": "20161101",
"Hist" : 165.3,
"Current": 158.2
},
{
"Item": "3",
"AwdDate": "201700101",
"Hist": 160,
"Current": 165
},
{
"Item": "4",
"AwdDate": "201600401",
"Hist": 173,
"Current": 177
}
]
}; 编辑2这里是我为这里提供的解决方案的尝试。但是,在控制器的onInit()函数中包含了这一点之后,什么也不会出现。
var regressionData = [];
for (var i = 0; i < 10; i++) {
regressionData[i] = [oData.ProductCollection[i].Current, oData.ProductCollection[i].Hist];
};
regression('linear', regressionData); 发布于 2017-03-25 09:58:40
不幸的是,您有一些固有的限制,即图表。即:
此外,您的X值(AwDate)是字符串的ABAP样式日期.更恰当的做法是使用日期/时间图来正确显示它们。无论如何,当您使用日期时,回归更有意义。否则,您的数据是“绝对的”,唯一可以进行回归的方法是对它们进行排序,并在X轴上考虑它们的等距--如果您有非等距数据(如您的示例中的数据),则不会像通常所希望的那样。
我的建议是:
按照要求,我在这里做了一个示例实现:https://jsfiddle.net/93mx0yvt/23/。我从这里借用的回归算法:https://dracoblue.net/dev/linear-least-squares-in-javascript/。守则的要点是:
// format for parsing the ABAP-style dates
var oFormat = DateFormat.getDateInstance({
pattern: "yyyyMMdd"
});
// maps an ProductCollection entry to a new object
// which has the parsed date (and only the needed attributes)
var fnMapData = function(oEntry) {
return {
date: oFormat.parse(oEntry.AwdDate),
current: oEntry.Current,
historical: oEntry.Hist
};
};
var fnProcessData = function(oD) {
var aEntries = oD.ProductCollection.map(fnMapData),
aXs = aEntries.map(function(oE) { // get the Xs
// we take the millis to be able to do arithmetics
return oE.date.getTime();
}),
aYs = aEntries.map(function(oE) { // get the Ys (hist)
return oE.historical;
}),
//changed the function to only return only result Ys
aRs = findLineByLeastSquares(aXs, aYs);
//save the Ys into the result
for (var i = 0; i < aEntries.length; ++i) {
aEntries[i].trend = aRs[i];
}
return {
data: aEntries
};
};然后,您可以使用fnProcessData函数在JSONModel中返回的数据,然后在此基础上构建一个简单的多序列日期/时间线图。
https://stackoverflow.com/questions/42939004
复制相似问题