describe "Team::Membership" do
let(:team) { Team.last }
let(:user) { User.last }
let(:membership) {user.apply_for(team)}
it "can be rejected" do
assert_difference "team.denied_applications.reload.count", +1 do
assert_difference "team.applications.reload.count", -1 do
assert_difference "team.members.reload.count", 0 do
membership.reject!
end
end
end
membership.state.must_equal "denied"
end如果应用程序被拒绝,那么范围denied_applications会增加1,applications是-1,members根本不会改变。
# team.rb
has_many :memberships, dependent: :destroy
has_many :members, -> { where(team_memberships: {state: :confirmed}) }, through: :memberships, source: :user
has_many :ex_members, -> { where(team_memberships: {state: :left}) }, through: :memberships, source: :user
has_many :applications, -> { where(state: :pending) }, class_name: "Membership"
has_many :denied_applications, -> { where(state: :denied) }, class_name: "Membership"所以我的问题更有可能是:这是一个好的写作测试,还是你只需要写
team.denied_applications.reload.count.must_equal(1)
team.applications.reload.count.must_equal(0)
team.members.reload.count.must_equal(0)发布于 2017-03-09 08:49:31
有些人会争辩说,不同的断言应该在不同的测试中,但是IMHO,在这种情况下不是问题。
在我看来最不理想的是,你打电话给
let(:team) { Team.last }
let(:user) { User.last }为了确保您的测试不相互依赖或相互干扰,应该在测试运行期间清除数据库,因此如果这样做了,您可以编写如下内容:
let(:team) { Team.create }
let(:user) { User.create }或者您可以使用像factory_girl这样的工具来更容易地创建记录,例如,如果您正在进行一些验证,并且不想在任何地方键入有效的数据。
https://stackoverflow.com/questions/42687971
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