如何使用JSTL迭代列表

Question

我有这样一个列表，所有的用户问题都会被分配。

userId      issueNo     issue_desc                  comments
amit        t12334      login not happening         login via test user not happening
amit        t1666       session is not cleared      after logout session is not cleared
yash        st5436      Transaction Logs            check transaction logs           

如何使用JSTL实现以下功能？

amit
issueNo             issue_desc                      comments
12334               login not happening             login via test user not happening
t1666               session is not cleared          after logout session is not cleared

yash
issueNo             issue_desc                      comments
st5436              Transaction Logs                check transaction logs

或者有什么更好的方法来展示这个？

Answer 1

1)按“用户标识”对用户列表进行排序；

2)使用下一个周期：

<table>
  <thead>
    <th>issueNo</th>
    <th>issue_desc</th>
    <th>comments</th>
  </thead>
  <tbody> 
<c:forEach items="${users}" var="user">
  <c:if test="${empty prevUser or user.userId != prevUser.userId}">
    <tr>
      <td colspan='3' align='left'><c:out value="${user.userId}"/></td>
    </tr>
  </c:if>
  <tr>
    <td><c:out value="${user.issueNo}"/></td>
    <td><c:out value="${user.issue_desc}"/></td>
    <td><c:out value="${user.comments}"/></td>
  </tr>
  <c:set var="prevUser" value="${user}" />
</c:forEach>
  </tbody>
</table>