iOS - searchBar，错误

Question

我试图在searchBar中实现tableView，但是我得到了这个错误。我想不出怎么把它移走。

func searchBar(_ searchBar: UISearchBar, textDidChange searchText: String) {
    searchingDataArray = origanalArray.filter({ (text) -> Bool in
        let tmp: String = text
        let range = tmp.range(of: searchText, options: NSString.CompareOptions.caseInsensitive)
        return range.location != NSNotFound
    })
    if (searchingDataArray.count == 0) {
        searching = false
    } else {
        searching = true
    }
    self.tableView.reloadData()
}

此错误出现在代码的第5行，听起来如下所示:类型范围的值string.index没有成员位置

Answer 1

更新为Swift 3：

使用代码行；

// MARK:- Varirabl Declartion

@IBOutlet weak var mSearchBar: UISearchBar!
@IBOutlet weak var mTableView: UITableView!

var isSearch : Bool = false
var arrCountry = ["Afghanistan", "Algeria", "Bahrain","Brazil", "Cuba", "Denmark","Denmark", "Georgia", "Hong Kong", "Iceland", "India", "Japan", "Kuwait", "Nepal"]
var arrFilter:[String] = []

//标记: UISearchBar代表方法

func searchBar(_ searchBar: UISearchBar, textDidChange searchText: String) {

    if searchText.characters.count == 0 {
        isSearch = false;
        self.mTableView.reloadData()
    } else {
        arrFilter = arrCountry.filter({ (text) -> Bool in
            let tmp: NSString = text as NSString
            let range = tmp.range(of: searchText, options: NSString.CompareOptions.caseInsensitive)
            return range.location != NSNotFound
        })
        if(arrFilter.count == 0){
            isSearch = false;
        } else {
            isSearch = true;
        }
        self.mTableView.reloadData()
    }
}

Answer 2

试试这个可能对你有帮助：

  func searchBar(searchBar: UISearchBar, textDidChange searchText: String) {

    filtered = data.filter({ (text) -> Bool in
        let tmp: NSString = text
        let range = tmp.rangeOfString(searchText, options: NSStringCompareOptions.CaseInsensitiveSearch)
        return range.location != NSNotFound
    })
    if(filtered.count == 0){
        searchActive = false;
    } else {
        searchActive = true;
    }
    self.tableView.reloadData()
}