我有一个问题,在相同的模块,我上一次张贴在下面的帖子。看起来,处理XML解析是相当困难的。elementTree的文档非常丰富。
下面有一个template_XML文件:
<?xml version="1.0" encoding="UTF-8"?>
<Tailoring xmlns="http://checklists.nist.gov/xccdf/1.2" id="xccdf_org.open-scap_tailoring_example">
<status>incomplete</status>
<version time="2013-01-15T16:00:00.000+02:00">1.0</version>
<Profile id="PlaceHolder">
<title>Tailoring for py_test</title>
<select idref="xccdf_rule_name" selected="true"/>
</Profile>
</Tailoring>以及下面的sample_XML文件:
<Benchmark xmlns="http://checklists.nist.gov/xccdf/1.1" xmlns:xsi="www.w3.org/2001/XMLSchema-instance" id="SAP-HANA" resolved="1" xml:lang="en-US">
<status date="2016-03-17">draft</status>
<title xmlns:xhtml="http://www.w3.org/1999/xhtml" xml:lang="en-US">Guide to the Secure Configuration of SAP HANA</title>
<version>0.1.28</version>
<Profile id="profile1">
<title xmlns:xhtml="http://www.w3.org/1999/xhtml" xml:lang="en-US">text1</title>
<select idref="This is rule 1" selected="true"/>
<set-value idref="ssfs_master_key_timeout">20</set-value>
</Profile>
<Profile id="profile2">
<title xmlns:xhtml="http://www.w3.org/1999/xhtml" xml:lang="en-US">text2</title>
<select idref="this is rule1" selected="true"/>
<select idref="this is rule1" selected="true"/>
<select idref="this is rule1" selected="true"/>
</Profile>
</Benchmark>我需要创建一个new_xml文件,一个 template_XML文件的副本。但希望将new_xml文件中的“PlaceHolder”配置文件标记替换为sample_XML文件的"profile2“标记。它是2 xml文件的一种合并,并创建了一个新的xml文件。下面是我尝试过的代码:
function call(id){
var template_XML = 'C:\\MyDrive\\template_XML';
var new_xml = 'C:\\MyDrive\\new_xml';
data = fs.readFileSync(template_XML).toString();
data1 = fs.readFileSync(sample_XML).toString();
etree = et.parse(data);
etree1 = et.parse(data1);
var profile = etree.find('./Profile'); // Getting the profile sub-element.
etree.getroot().remove(profile) // Removing the sub-element. So that I can insert new profile from sample file
var profiles = etree1.findall('./Profile'); // Find the required profile.
for (var i = 0; i < profiles.length; i++) {
if(profiles[i].get('id') == 'profile2')
var tmppro = profiles[i];
}
console.log(tmppro);
etree.insert(3,tmppro); // insert it. Failing
var write = fs.openSync(new_xml, 'w');
etree.write(write); // write it. Failing
}由于某种原因,这段代码不适用于"etree.insert“和"etree.write”。
发布于 2017-03-03 07:29:25
最后,我使它能够使用当前的库。请参阅我的评论:
'use strict';
const et = require('elementtree');
const path = require('path');
const fs = require('fs');
function populateXmlTemplate(id) {
//Please use path.join to make it cross-platform
var template_XML = path.join(__dirname, 'template.xml');
var sample_XML = path.join(__dirname, 'sample.xml');
var new_xml = path.join(__dirname, 'new.xml');
var data = fs.readFileSync(template_XML).toString();
var data1 = fs.readFileSync(sample_XML).toString();
var etree = et.parse(data);
var etree1 = et.parse(data1);
var root = etree.getroot();
var placeholder = root.find('./Profile');
root.remove(placeholder);
var profiles = etree1.findall('./Profile'); // Find the required profile.
for (var i = 0; i < profiles.length; i++) {
//If I get it right, it shouldn't be hardcoded
if (profiles[i].get('id') == id) {
var tmppro = profiles[i];
}
}
//After you removed the placeholder the number of children decreased
//So it should be 2, not 3.
//Also etree doesn't have insert method, please call root.insert
root.insert(2, tmppro);
//You have been writing the document a bit incorrectly.
var resultXml = etree.write();
fs.writeFileSync(new_xml, resultXml);
}
populateXmlTemplate('profile2');
module.exports = {populateXmlTemplate};
但你是对的,文件不是很好。基本上不见了。因此,大多数情况下,我只是为了查看可用的方法而使用调试,在lib中也有一些测试。
还有其他模块可以使用js。请看这个回答。
https://stackoverflow.com/questions/42553153
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