我正在搜索如何使用服务来获取用户的数据
users.services.ts
import { AngularFire, AuthProviders, AuthMethods, FirebaseListObservable}
export class Users {
uid :string = '8fbEOShqIigfA4u84cyvJcLkv5u1';
constructor(public af: AngularFire) {}
getUserObservable(){
return this.af.database.object('/users/' + this.uid);
}
}在这里我的home.ts
import { Users } from '../../services/users.service';
@Component({
selector: 'page-home',
templateUrl: 'home.html'
})
export class HomePage {
user: any;
isAuthenticated: boolean = true;
constructor(private userService: Users) {}
ngOnInit(){
this.userService.getUserObservable().subscribe((userObject) => {
this.user = userObject;
console.log("result : ", this.user);
});
}
}在控制台我得到:
result : Object {imgLink: "blabla.jpg", money: 0, score: 0, uid: "8fbEOShqIigfA4u84cyvJcLkv5u1", username: "Luis Willnat"…}但从离子的角度来看:
Cannot read property 'money' of undefined我想是因为异步(我练习得不够好),但不知道是什么..
非常感谢你的帮助:)
发布于 2017-02-27 22:20:23
您需要以不同的方式设置代码。通常,当服务包装异步调用--任何异步调用,而不仅仅是Firebase的-时,它的方法应该返回可观测值,而不是由可观测值发出的值。
即使您愿意,也不方便(或可能)尝试返回包装在可观察范围内的值,因为它们只有在可观察到的发射时才可用,而且您无法控制它何时出现。
根据这些准则,您的代码变成:
@Injectable()
export class UserService {
constructor(public af: AngularFire) {}
getUser() {
// Return the observable. DO NOT subscribe here.
return this.af.auth;
// Hint: you could also transform the value before returning it:
// return this.af.auth.map(authData => new User({name: authData.name}));
}
}然后,在组件中或在需要的地方,订阅以获得用户:
ngOnInit() {
this.userService.getUser()
.subscribe(user => this.user = user);
}https://stackoverflow.com/questions/42494604
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