如何在python中使用regexp匹配按"-“划分的单词组

Question

我使用python2.7，并试图将某个字符串与此结构匹配：

INPUT = 'abc-1-2 abc-2-3 abc-1-1 - TYP1 xyz-2-3 xyzzz - TYP2 ooop-1-1 abc-3-3 bbb - TYP3'

EXPECTED_OUTPUT = [
    'abc-1-2 abc-2-3 abc-1-1 - TYP1',
    'xyz-2-3 xyzzz - TYP2',
    'ooop-1-1 abc-3-3 bbb - TYP3']

这是我尝试过的解决方案，但它不起作用：在线演示

Answer 1

我想这就是你要找的：

".+?TYP\d+"

Answer 2

下面的regex应该这样做：

\b.*?-\s.*?(?:\s|$)

请参阅https://regex101.com/r/hCWuF3/2

python

import re
regex = ur"\b.*?-\s.*?(?:\s|$)"
str = "abc-1-2 abc-2-3 abc-1-1 - TYP1 xyz-2-3 xyzzz - TYP2 ooop-1-1 abc-3-3 bbb - TYP3"
matches = re.finditer(regex, str)
for matchNum, match in enumerate(matches):
    matchNum = matchNum + 1
    print ("{match}".format(matchNum = matchNum, start = match.start(), end = match.end(), match = match.group()))

Answer 3

>>> re.findall(r'\S.*? - \S+', INPUT)
['abc-1-2 abc-2-3 abc-1-1 - TYP1', 'xyz-2-3 xyzzz - TYP2', 'ooop-1-1 abc-3-3 bbb - TYP3']

解释：

'\S'  # any non-space character
'.*?' # (.) any character (*) zero or more times (?) non-greedy (match as few as possible)
' - ' # literal space dash space
'\S'  # any non-space character
'+'   # one or more times