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社区首页 >问答首页 >错误“未定义的引用”

错误“未定义的引用”
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Stack Overflow用户
提问于 2017-02-25 14:49:15
回答 1查看 70关注 0票数 0

我在C中创建了一个基本脚本,但控制台中出现了一个奇怪的错误。谁能告诉我为什么我的剧本会给我这样的信息:

对“is_substance_within_x_percent”的未定义引用

源代码:

代码语言:javascript
复制
#include<stdio.h>
#include<stdlib.h>
#include<math.h>   
#define P 0.3    

#ifndef BOILING_POINTS_H    
#define BOILING_POINTS_H    
#define SUBSTANCE_CARBONDIOXIDE  -78.5    
#define SUBSTANCE_AMMONIA        -35.5    
#define SUBSTANCE_WAX             45.0    
#define SUBSTANCE_WATER          100.7    
#define SUBSTANCE_OLIVE_OIL      300.0    
#define SUBSTANCE_MERCURY        356.9    
#define SUBSTANCE_SULFUR         444.6    
#define SUBSTANCE_TALC          1500.0    
#define SUBSTANCE_SILVER        2212.0    
#define SUBSTANCE_COPPER        2562.0        
#define SUBSTANCE_GOLD          2700.0    
#define SUBSTANCE_IRON          2862.0    
#define SUBSTANCE_SILICON       3280.0    
#endif    

int is_substance_within_x_percent(double t,double p,double boils);

int main( )    
{
    double t, p, boils;    
    int substance;    

    is_substance_within_x_percent(t, p, boils);    

    printf("Enter the boiling temperature of the substance.\n");    
    scanf("%lf", &t);    

    return EXIT_SUCCESS;    
}

char * substance_name(double t,int substance)    
{
    if (t >= SUBSTANCE_CARBONDIOXIDE - P *substance && t <= SUBSTANCE_CARBONDIOXIDE + P *substance)    
    printf("The substance found is Carbon Dioxyde");    

    else if (t >= SUBSTANCE_AMMONIA - P *substance && t <= SUBSTANCE_AMMONIA + P *substance)    
    printf("The substance found is Ammonia");    

    else if (t >= SUBSTANCE_WAX - P *substance && t <= SUBSTANCE_WAX + P *substance)    
    printf("The substance found is Wax");    

    else if (t >= SUBSTANCE_WATER - P *substance && t <= SUBSTANCE_WATER + P *substance)    
    printf("The substance found is Water");    

    else if (t >= SUBSTANCE_OLIVE_OIL - P *substance && t <= SUBSTANCE_OLIVE_OIL + P *substance)    
    printf("The substance found is Olive Oil");    

    else if (t >= SUBSTANCE_MERCURY - P *substance && t <= SUBSTANCE_MERCURY + P *substance)    
    printf("The substance found is Mercury");    

    else if (t >= SUBSTANCE_SULFUR - P *substance && t <= SUBSTANCE_SULFUR + P *substance)    
    printf("The substance found is Sulfur");    

    else if (t >= SUBSTANCE_TALC - P *substance && t <= SUBSTANCE_TALC + P *substance)    
    printf("The substance found is Talc");    

    else if (t >= SUBSTANCE_SILVER - P *substance && t <= SUBSTANCE_SILVER + P *substance)    
    printf("The substance found is Silver");    

    else if (t >= SUBSTANCE_COPPER - P *substance && t <= SUBSTANCE_COPPER + P *substance)    
    printf("The substance found is Copper");    

    else if (t >= SUBSTANCE_GOLD - P *substance && t <= SUBSTANCE_GOLD + P *substance)    
    printf("The substance found is Gold");    

    else if (t >= SUBSTANCE_IRON - P *substance && t <= SUBSTANCE_IRON + P *substance)    
    printf("The substance found is Iron");    

    else if (t >= SUBSTANCE_SILICON - P *substance && t <= SUBSTANCE_SILICON + P *substance)    
    printf("The substance found is Silicon");    

    else    
    printf("This substance is unidentified.");    
}
EN

回答 1

Stack Overflow用户

发布于 2017-02-25 15:38:54

首先,将第二个函数的名称更改为is_substance_within_x_percent

第二,你主要不使用物质。

第三,为什么要扫描而不使用它。

第四,基本上,您声明了三个双参数,并将它们传递给一个函数,而不知道其中包含了什么。

票数 -2
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页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/42457523

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