Selenium3 Python3如何从属性style=获取url“背景-图像: ur，”并且有一个url

Question

要从属性url获取url，我的意思是url本人的风格？Style=“宽度:433 for；高度:510 for；背景图像: url(https://cs7056.vk.me/c635104/v635104607/1c316/ADzy-2WY8pw.jpg)”Selenium3 Python3轻松为您！

import requests
from bs4 import BeautifulSoup
from selenium import webdriver
from selenium.webdriver.common.by import By
from selenium.webdriver.common.keys import Keys
from selenium.common.exceptions import NoSuchElementException
from selenium.common.exceptions import NoAlertPresentException
import re
import time


url = 'https://vk.com/uporols_you'
driver                          = webdriver.Firefox(executable_path='C:/Users/PANDEMIC/AppData/Local/Mozilla/geckodriver.exe')

def login(driver):
    log_page                    = driver.get('https://login.vk.com/?act=login')
    find_login_input            = driver.find_element_by_id('login_form').find_element_by_id('email').send_keys('+77782303865')
    find_password_input         = driver.find_element_by_id('login_form').find_element_by_id('pass').send_keys('pass')
    find_button                 = driver.find_element_by_xpath('//button[@id="login_button"]').click()
    time.sleep(5)



def get_photo_from_page(driver):
    driver.get(url)
    try:
        driver.find_element_by_class_name('popup_box_container').find_element_by_class_name('box_title_wrap').find_element_by_class_name('box_x_button').click()
    except:
        print('nope nothing')

    for i in range(2):
        scrol_down = driver.find_element_by_id('public_wall').find_element_by_id('wall_more_link').click()
        time.sleep(2)

    tut = []
    #t = (a[@class="page_post_thumb_wrap image_cover  page_post_thumb_last_column page_post_thumb_last_row"])
    for ii in driver.find_elements_by_xpath('//a[@style]'):
        o = ii.get_attribute('style')
        print(o)
    #soup = BeautifulSoup(htlm, 'lxml')
    #im = soup.find_all('a', class_="'page_post_thumb_wrap image_cover  page_post_thumb_last_column page_post_thumb_last_row'")
    #print(htlm)
    #for a in im:
    #   s = a.get('data-src_big').split('|')[0]
    #   tut.append(s)
    #print(tut) 

    #for num, link in enumerate(tut, start=1):
    #   p = requests.get(link)
    #   out = open("img%s.jpg" % (num), 'wb')
    #   out.write(p.content)
    #   out.close()


def main():
    login(driver)
    get_photo_from_page(driver)


if __name__ == '__main__':
    main()

Answer 1

在这种情况下，您只需解析已经能够在脚本中收集到的样式字符串。

只需将此函数添加到代码中：

def parse_style_attribute(style_string):
    if 'background-image' in style_string:
        style_string = style_string.split(' url("')[1].replace('");', '')
        return style_string
    return None

这是一个简单的字符串解析，如果字符串中有“背景图像”，则提取url；如果没有图像，则返回None。

然后，您可以在代码中使用它：

links = list()
for ii in driver.find_elements_by_xpath('//a[@style]'):
    o = ii.get_attribute('style')
    links.append(parse_style_attribute(o))
links = [link for link in links if link is not None]