如何在RESTful ESB中集成WSO2服务

Question

我试图通过WSO2 ESB (RESTful )创建一个集成层。

端点- http://www.thomas-bayer.com/

上下文- /sqlrest

和

URI-模板- /CUSTOMER/3

( API Endpoint -www.thoms-bayer.com/sqlrest/CUSTOMER/3)

之后，当我试图用( http://localhost:8280:/sqlrest/CUSTOMER/3 )调用api请求时

我得到的响应是带有404错误代码的完整HTML，而不是XML数据。

Answer 1

您可以在WSO2 ESB中使用此API：

<?xml version="1.0" encoding="UTF-8"?>
<api xmlns="http://ws.apache.org/ns/synapse"
     name="sqlrestAPI"
     context="/sqlrest">
   <resource methods="GET" protocol="http" uri-template="/CUSTOMER/{id}">
      <inSequence>
         <log level="full"/>
         <send>
            <endpoint>
               <http method="GET"
                     uri-template="http://www.thomas-bayer.com/sqlrest/CUSTOMER/{uri.var.id}"/>
            </endpoint>
         </send>
      </inSequence>
      <outSequence>
         <send/>
      </outSequence>
      <faultSequence/>
   </resource>
</api>

并调用它(在我的例子中，偏移量=3)：

curl -v http://localhost:8283/sqlrest/CUSTOMER/3

答复：

* About to connect() to localhost port 8283 (#0)
*   Trying 127.0.0.1...
* connected
* Connected to localhost (127.0.0.1) port 8283 (#0)
> GET /sqlrest/CUSTOMER/3 HTTP/1.1
> User-Agent: curl/7.25.0 (i386-pc-win32) libcurl/7.25.0 OpenSSL/0.9.8u zlib/1.2.6 libssh2/1.4.0
> Host: localhost:8283
> Accept: */*
>
< HTTP/1.1 200 OK
< Content-Type: application/xml
< Date: Thu, 26 Jan 2017 16:40:08 GMT
< Transfer-Encoding: chunked
<
<?xml version="1.0"?><CUSTOMER xmlns:xlink="http://www.w3.org/1999/xlink">
    <ID>3</ID>
    <FIRSTNAME>Michael</FIRSTNAME>
    <LASTNAME>Clancy</LASTNAME>
    <STREET>542 Upland Pl.</STREET>
    <CITY>San Francisco</CITY>
</CUSTOMER>* Connection #0 to host localhost left intact
* Closing connection #0

Answer 2

您提供的上下文不需要是来自实际端点URL的任何内容。

例如，可以将上下文定义为myapi。那么你有两个选择。

选项1:

将端点配置为http://www.thomas-bayer.com/

然后，您可以将API称为http://localhost:8280/myapi/sqlrest/CUSTOMER/3。

备选方案2:

将端点配置为http://www.thomas-bayer.com/sqlrest/

然后，您可以将API称为http://localhost:8280/myapi/CUSTOMER/3。