$mengetotzut = 7','8','9','22','23','24','25 ;
$zutatiddd = 42','75','8','90','23','82','33 ;
$sql5= "UPDATE zutaten SET Menge=('$mengetotzut') WHERE Zutat_ID IN('$zutatiddd')";
$run_query = mysqli_query($con,$sql5);如SQL语句所示:
UPDATE zutaten SET Menge=('42','75','8','90','23','82','33') WHERE Zutat_ID IN('7','8','9','22','23','24','25')我想做的是:
Update Menge='42' Where Zutat_ID is '7' AND Update Menge ='75' Where Zutat_ID = '8' ...但是在一个SQL语句中。有人能告诉我这是否可能吗?我该怎么做?
发布于 2017-01-18 10:12:45
考虑到两个数组具有相同的计数,请尝试以下方法
$count = 7;
for ($i=0; $i<$count; $i++) {
$sql5= "UPDATE zutaten SET Menge=$mengetotzut[$i] WHERE Zutat_ID = $zutatiddd[$i]";
$run_query = mysqli_query($con,$sql5);
}发布于 2017-01-18 10:09:09
使用前馈回路
foreach( $mengetotzut as $index => $code ) {
$sql5= "UPDATE zutaten SET Menge=('$code') WHERE Zutat_ID = $zutatiddd[$index];
$run_query = mysqli_query($con,$sql5);
}发布于 2017-01-18 10:13:27
您可以使用SQL查询,如下所示,只需一次就可以使用UPDATE:
UPDATE zutaten AS t1
JOIN (
SELECT 7 AS Zutat_ID, 42 AS Menge
UNION ALL
SELECT 8, 75
UNION ALL
SELECT 9, 8
) t2 ON t1.Zutat_ID = t2.Zutat_ID
SET t1.Menge = t2.Mengehttps://stackoverflow.com/questions/41716385
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