blocks|key|276951|text|若要使Race按需要成为关联类，请使水平连接器破折号并删除多重性。上面显示的是一种三元连接器(请参阅讨论)。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|276952|​|276953|📷|atomic|276954|276955|这相当于|276956|276957|276958|276959|多重0..1告诉我们，每个赛季和赛道都有一次或没有一场比赛。|276960|entityMap|0|IMAGE|mutability|IMMUTABLE|imageUrl|https://developer.qcloudimg.com/http-save/yehe-900000/552736108339d12e7739e68517639a32.png|imageAlt|1|https://developer.qcloudimg.com/http-save/yehe-900000/2993db343d00b84db81fe6d59d994e6f.png^0|3|4|0|0|0|1|0|0|0|0|0|0|1|1|0|0|2|4|0^^$0|@$1|2|3|4|5|6|7|13|8|@$9|14|A|15|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|16|8|@]|D|@]|E|$]]|$1|H|3|I|5|J|7|17|8|@]|D|@$9|18|A|19|1|1A]]|E|$]]|$1|K|3|G|5|6|7|1B|8|@]|D|@]|E|$]]|$1|L|3|M|5|6|7|1C|8|@]|D|@]|E|$]]|$1|N|3|G|5|6|7|1D|8|@]|D|@]|E|$]]|$1|O|3|I|5|J|7|1E|8|@]|D|@$9|1F|A|1G|1|1H]]|E|$]]|$1|P|3|G|5|6|7|1I|8|@]|D|@]|E|$]]|$1|Q|3|R|5|6|7|1J|8|@$9|1K|A|1L|B|C]]|D|@]|E|$]]|$1|S|3|-4|5|6|7|1M|8|@]|D|@]|E|$]]]|T|$U|$5|V|W|X|E|$Y|Z|10|-4]]|11|$5|V|W|X|E|$Y|12|10|-4]]]]

To make <code>Race</code> an association class as desired, make the horizontal connector dashed and remove the multiplicities. The above currently shows sort of a ternary connector (see discussion).

<a href="https://i.stack.imgur.com/wSEzJ.png" rel="nofollow noreferrer"><img src="https://i.stack.imgur.com/wSEzJ.png" alt="enter image description here"></a>

This is equivalent to

<a href="https://i.stack.imgur.com/C4efr.png" rel="nofollow noreferrer"><img src="https://i.stack.imgur.com/C4efr.png" alt="enter image description here"></a>

The multiplicity <code>0..1</code> tells that there is one or no race per season and circuit.

blocks|key|2130722|text|根据我的理解，以下图表按需要对情况进行了建模：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2130723|​|2130724|📷|atomic|offset|length|2130725|2130726|每一季都可能与*线路有种族联系，反之亦然。如果一个特定的季节与特定的电路有种族关联，那么该关联正好有一个种族关联类实例。|2130727|一个赛季不一定要和赛道联系在一起，这样的组合就没有比赛可言了。|2130728|现在，每个赛季的赛道组合最多有一场比赛的限制从何而来？这是因为在一个关联端上有一个*(或任何数字>+1)意味着一个实例可能与多个不同的其他实例相关联，而不是与一个和另一个实例关联几次。|style|BOLD|2130729|在本例中，一个季节实例可以与几个不同的电路相关联，但不能与一个和同一个电路相关联几次。(如果您想要对此进行建模，则必须使用多个协会或有资格的协会)|2130730|entityMap|0|IMAGE|mutability|IMMUTABLE|imageUrl|https://developer.qcloudimg.com/http-save/yehe-900000/5356d149e5440198a9d3efb05ff5fa8e.png|imageAlt^0|0|0|0|1|0|0|0|0|0|1S|3|0|0^^$0|@$1|2|3|4|5|6|7|12|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|13|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|14|8|@]|9|@$G|15|H|16|1|17]]|A|$]]|$1|I|3|C|5|6|7|18|8|@]|9|@]|A|$]]|$1|J|3|K|5|6|7|19|8|@]|9|@]|A|$]]|$1|L|3|M|5|6|7|1A|8|@]|9|@]|A|$]]|$1|N|3|O|5|6|7|1B|8|@$G|1C|H|1D|P|Q]]|9|@]|A|$]]|$1|R|3|S|5|6|7|1E|8|@]|9|@]|A|$]]|$1|T|3|-4|5|6|7|1F|8|@]|9|@]|A|$]]]|U|$V|$5|W|X|Y|A|$Z|10|11|-4]]]]

According to my understanding the following diagram models the situation as desired:

<a href="https://i.stack.imgur.com/Q2XH1.png" rel="nofollow noreferrer"><img src="https://i.stack.imgur.com/Q2XH1.png" alt="UML diagram"></a>

Each season may have Race associations with * circuits and vice versa. If a specific season has a Race association with a specific circuit, then the association has exactly one Race association class instance.

A season doesn't have to be associated with a circution, then there's no race for this combination.

Where does the restriction of having at most one race for each season - circuit combination now come from? This is due to the fact that having a * (or any number > 1) on one association end means that an instance may be associated with more than 1 different other instances, but not several times with one and the same other instance.

In this example, a season instance may be associated with several different circuits, but not several times with one and the same circuit. (If you'd like to model this, you'd have to use e.g. multiple associations or a qualified association)

I have a piece of statement that I don't understand how to model it in a class diagram. It is about Formula 1 races. The piece is the following:

<blockquote>
 We can only have one race per circuit in each season
</blockquote>

So there is a relationship between CIRCUIT, SEASON and RACE.

<hr>

I believe that it is a ternary association, but a mate told me that it could be an association between CIRCUIT - SEASON and then an association between that association and RACE: 

<a href="https://i.stack.imgur.com/F0l9r.png" rel="nofollow noreferrer"><img src="https://i.stack.imgur.com/F0l9r.png" alt="Association of an association diagram"></a>

Is that picture wrong? I mean, association should be between 2 classes as far as I know. Not between a class and an association...

Thank's you very much!!!!

EDIT:
The statement was wrong, I restated it and could be translated in: (imagine we have 3 circuits)

<ul>
<li>Circuit A in Season 1 --> Race 1</li>
<li>Circuit B in Season 1 --> Race 2</li>
<li>Circuit C in Season 1 --> Race 3</li>
<li>Circuit A in Season 1 --> Race 4 (This should not be allowed, we can only have one race per circuit in each season)</li>
<li>Circuit A in Season 2 --> Race 5 (This is correct)</li>
</ul>

We can only have 1 race per circuit in each season

UML - Association between 3 classes

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我有一条声明，我不知道如何在类图中对其建模。这是关于一级方程式比赛的。该作品如下：我们每个赛季只能有一场比赛。因此，电路、旺季和之间存在着一定的联系。我相信这是一种三元关联，但一位配偶告诉我，这可能是巡回季之间的关联，然后是与和之间的关联：​​这幅画错了吗？我的意思是，据我所知，两个班之间应该有联系。不是在阶级和社团之间..。非常感谢你！编辑：语句是错误的，我重申了它，可以翻译成：(假设我们有3个

问UML -三个类之间的关联
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