使用rxjs5分配对象

Question

Hy，创建对象和使用rxjs5可观测值的功能方法是什么？

let _id = myObservableOne.pluck('id')
let _name = myObservableSecond.pluck('name')
let _path = myObservableThird.pluck('path')

let newObj = {
   id: _id,
   name: _name,
   path: _path
}

Answer 1

根据所有三个可观测值的值排放率是否相等，.zip()操作符可能会做您需要的事情：

const idStream = myObservableOne.pluck('id')
const nameStream = myObservableSecond.pluck('name')
const pathStream = myObservableThird.pluck('path')

Rx.Observable.zip(
  idStream,
  nameStream,
  pathStream,
  (id, name, path) => ({ id, name, path})
)
.subscribe(console.log);