在C# 7中，是否可以将元组解构为方法参数？

Question

例如，我有

private void test(Action<ValueTuple<string, int>> fn)
{
    fn(("hello", 10));
}

test(t => 
 {
    var (s, i) = t;
    Console.WriteLine(s);
    Console.WriteLine(i);
});

我想写这样的东西

private void test(Action<ValueTuple<string, int>> fn)
{
    fn(("hello", 10));
}

test((s,i) => 
{
    Console.WriteLine(s);
    Console.WriteLine(i);
});

这有可能用适当的符号表示吗？

Answer 1

你可以把它缩短到：

void test( Action<ValueTuple<string, int>> fn)
{
    fn(("hello", 10));
}

test(((string s, int i) t) =>
{
    Console.WriteLine(t.s);
    Console.WriteLine(t.i);
});

希望有一天我们能够将参数从元组拆分到方法调用：

void test(Action<ValueTuple<string, int>> fn)
{
    fn(@("hello", 10)); // <-- made up syntax
}

test((s, i) =>
{
    Console.WriteLine(s);
    Console.WriteLine(i);
});

但现在不行。

Answer 2

I. Action /Func委托的示例，它们具有distinct args vs. single n-tuple参数：

// 1. Action with 3 distinct 'int' parameters
Action<int, int, int> ArgsAction = (i1, i2, i3) => i1 += i2 += i3;

// 2. Func with 3 distinct 'int' parameters, returning 'long'
Func<int, int, int, long> ArgsFunc = (i1, i2, i3) => (long)i1 + i2 + i3;

// 3. Action with a single 3-tuple parameter
Action<(int, int, int)> TupleAction = args => args.Item1 += args.Item2 += args.Item3;

// 4. Action with a single 3-tuple parameter, returning 'long'
Func<(int, int, int), long> TupleFunc = args => (long)args.Item1 + args.Item2 + args.Item3;

II.演示了上述示例的直接用法。

long r;

// pass distinct params to multi-arg methods

ArgsAction(1, 2, 3);                // 1.

r = ArgsFunc(1, 2, 3);              // 2.

// pass tuple to tuple-taking methods

TupleAction((1, 2, 3));             // 3.

r = TupleFunc((1, 2, 3));           // 4.

下面两个部分中的示例以各自的非本机参数形式调用委托。若要延迟方法调用或保留用于缓存或延迟/多次调用的代理，请参见VII和VII。

III.分散("splat")将一个元组分成多个arg方法.

(1, 2, 3).Scatter(ArgsAction);      // 1.

r = (1, 2, 3).Scatter(ArgsFunc);    // 2.

IV.将不同的args传递给元组方法：

TupleAction.Gather(1, 2, 3);        // 3.

r = TupleFunc.Gather(1, 2, 3);      // 4.

V.扩展方法(III)和(IV)中使用的Scatter和Gather：

// disperse n-tuple into Action arguments
public static void Scatter<T0, T1>(in this (T0 i0, T1 i1) t, Action<T0, T1> a) => a(t.i0, t.i1);
public static void Scatter<T0, T1, T2>(in this (T0 i0, T1 i1, T2 i2) t, Action<T0, T1, T2> a) => a(t.i0, t.i1, t.i2);
public static void Scatter<T0, T1, T2, T3>(in this (T0 i0, T1 i1, T2 i2, T3 i3) t, Action<T0, T1, T2, T3> a) => a(t.i0, t.i1, t.i2, t.i3);

// disperse n-tuple into Func arguments
public static TResult Scatter<T0, T1, TResult>(in this (T0 i0, T1 i1) t, Func<T0, T1, TResult> f) => f(t.i0, t.i1);
public static TResult Scatter<T0, T1, T2, TResult>(in this (T0 i0, T1 i1, T2 i2) t, Func<T0, T1, T2, TResult> f) => f(t.i0, t.i1, t.i2);
public static TResult Scatter<T0, T1, T2, T3, TResult>(in this (T0 i0, T1 i1, T2 i2, T3 i3) t, Func<T0, T1, T2, T3, TResult> f) => f(t.i0, t.i1, t.i2, t.i3);

// accumulate 'n' distinct args and pass into Action as an n-tuple
public static void Gather<T0, T1>(this Action<(T0, T1)> a, T0 i0, T1 i1) => a((i0, i1));
public static void Gather<T0, T1, T2>(this Action<(T0, T1, T2)> a, T0 i0, T1 i1, T2 i2) => a((i0, i1, i2));
public static void Gather<T0, T1, T2, T3>(this Action<(T0, T1, T2, T3)> a, T0 i0, T1 i1, T2 i2, T3 i3) => a((i0, i1, i2, i3));

// accumulate 'n' distinct args and pass into Func as an n-tuple
public static TResult Gather<T0, T1, TResult>(this Func<(T0, T1), TResult> f, T0 i0, T1 i1) => f((i0, i1));
public static TResult Gather<T0, T1, T2, TResult>(this Func<(T0, T1, T2), TResult> f, T0 i0, T1 i1, T2 i2) => f((i0, i1, i2));
public static TResult Gather<T0, T1, T2, T3, TResult>(this Func<(T0, T1, T2, T3), TResult> f, T0 i0, T1 i1, T2 i2, T3 i3) => f((i0, i1, i2, i3));

VI.奖金回合.如果您计划以它的替代形式多次调用元组或不同的接受arg委托，或者如果您还没有准备好实际调用它，您可能希望显式地预先将委托从tuple-taking表单转换为等效的distinct args委托，反之亦然。您可以缓存转换后的委托，以便在以后进行多次或任意重用。

var ga = ArgsAction.ToGathered();        // 1.
// later...
ga((1, 2, 3));
// ...
ga((4, 5, 6));

var gf = ArgsFunc.ToGathered();          // 2.
// later...
r = gf((1, 2, 3));
// ...
r = gf((4, 5, 6));

var sa = TupleAction.ToScattered();      // 3.
// later...
sa(1, 2, 3);
// ...
sa(4, 5, 6);

var sf = TupleFunc.ToScattered();        // 4.
// later...
r = sf(1, 2, 3);
// ...
r = sf(4, 5, 6);

// of course these approaches also supports in-situ usage:

ArgsAction.ToGathered()((1, 2, 3));      // 1.
r = ArgsFunc.ToGathered()((1, 2, 3));    // 2.

TupleAction.ToScattered()(1, 2, 3);      // 3.
r = TupleFunc.ToScattered()(1, 2, 3);    // 4.

VII.第六章中所示奖金示例的扩展方法。

// convert tuple-taking Action delegate to distinct-args form
public static Action<T0, T1> ToScattered<T0, T1>(this Action<(T0, T1)> a) => (i0, i1) => a((i0, i1));
public static Action<T0, T1, T2> ToScattered<T0, T1, T2>(this Action<(T0, T1, T2)> a) => (i0, i1, i2) => a((i0, i1, i2));
public static Action<T0, T1, T2, T3> ToScattered<T0, T1, T2, T3>(this Action<(T0, T1, T2, T3)> a) => (i0, i1, i2, i3) => a((i0, i1, i2, i3));

// convert tuple-taking Func delegate to its distinct-args form
public static Func<T0, T1, TResult> ToScattered<T0, T1, TResult>(this Func<(T0, T1), TResult> f) => (i0, i1) => f((i0, i1));
public static Func<T0, T1, T2, TResult> ToScattered<T0, T1, T2, TResult>(this Func<(T0, T1, T2), TResult> f) => (i0, i1, i2) => f((i0, i1, i2));
public static Func<T0, T1, T2, T3, TResult> ToScattered<T0, T1, T2, T3, TResult>(this Func<(T0, T1, T2, T3), TResult> f) => (i0, i1, i2, i3) => f((i0, i1, i2, i3));

// convert distinct-args Action delegate to tuple-taking form
public static Action<(T0, T1)> ToGathered<T0, T1>(this Action<T0, T1> a) => t => a(t.Item1, t.Item2);
public static Action<(T0, T1, T2)> ToGathered<T0, T1, T2>(this Action<T0, T1, T2> a) => t => a(t.Item1, t.Item2, t.Item3);
public static Action<(T0, T1, T2, T3)> ToGathered<T0, T1, T2, T3>(this Action<T0, T1, T2, T3> a) => t => a(t.Item1, t.Item2, t.Item3, t.Item4);

// convert distinct-args Func delegate to its tuple-taking form
public static Func<(T0, T1), TResult> ToGathered<T0, T1, TResult>(this Func<T0, T1, TResult> f) => t => f(t.Item1, t.Item2);
public static Func<(T0, T1, T2), TResult> ToGathered<T0, T1, T2, TResult>(this Func<T0, T1, T2, TResult> f) => t => f(t.Item1, t.Item2, t.Item3);
public static Func<(T0, T1, T2, T3), TResult> ToGathered<T0, T1, T2, T3, TResult>(this Func<T0, T1, T2, T3, TResult> f) => t => f(t.Item1, t.Item2, t.Item3, t.Item4);

Answer 3

查看您的请求有两种方法，但在C# 7.0中都不支持这两种方法。

• 一种是将元组划分为参数:用元组调用方法，并将元组的元素拆分为该方法的不同参数。您现在可以通过调用M(tuple.first, tuple.second)手动完成此操作。
• 另一种是对lambda参数的解构:当用参数调用lambda时，将这些参数解构为元素，并在lambda体中使用这些元素。现在，您可以通过将lambda定义为x => { var (first, second) = x; Write(first); Write(second); }来手动完成此操作。

在csharplang设计回购中有一些建议正在讨论中。

• https://github.com/dotnet/csharplang/issues/424 (将元组划分为参数)
• https://github.com/dotnet/csharplang/issues/258 ( lambda参数的解构)