反应-本机-fbsdk洛金按钮工作不佳。

Question

我使用react本机-fbsdk 0.4.0，并遵循https://github.com/facebook/react-native-fbsdk中的步骤。在添加本机FBSDK和FB登录按钮后，我尝试了本机Object测试应用程序，没有问题。

然而，我也遇到了与这个帖子React Native Facebook Login using official fbsdk相同的问题。

import React, { Component } from 'react';
import {
  AppRegistry,
  StyleSheet,
  Text,
  View
} from 'react-native';

const FBSDK = require('react-native-fbsdk');
const {
  LoginButton,
  AccessToken
} = FBSDK;

var Login = React.createClass({
  render: function() {
    return (
      <View>
        <LoginButton
          publishPermissions={["publish_actions"]}
          onLoginFinished={
            (error, result) => {
              if (error) {
                alert("login has error: " + result.error);
              } else if (result.isCancelled) {
                alert("login is cancelled.");
              } else {
                AccessToken.getCurrentAccessToken().then(
                  (data) => {
                    alert(data.accessToken.toString())
                  }
                )
              }
            }
          }
          onLogoutFinished={() => alert("logout.")}/>
      </View>
    );
  }
});

AppRegistry.registerComponent('fbsdk_rn', () => Login);

真的很感谢你的帮助。谢谢。

更新：只是解决了我的问题，希望能激励其他人。我从https://github.com/magus/react-native-facebook-login上查看了这个“react原生-facebook-登录”。

整个过程几乎相同，只是"AppDelegate.m“中有一个不同的”头文件导入“

  #import <FBSDKCoreKit/FBSDKCoreKit.h>
  #import <FBSDKLoginKit/FBSDKLoginKit.h> 

我添加了FBSDKLoginKit.h的第二个导入，它可以工作。

Answer 1

--我正在使用这段代码--在我的例子中-- Login工作得很好，如果您可以使用这段代码，我确信您的按钮工作正常.

看这里的代码..。

<LoginButton   
          publishPermissions={["email"]}
          onLoginFinished={
            (error, result) => {
              if (error) {
                alert("Login failed with error: " + error.message);
              } else if (result.isCancelled) {
                alert("Login was cancelled");
              } else {
                alert("Login was successful with permissions: " + result.grantedPermissions)
              }
            }
          }
          onLogoutFinished={() => alert("User logged out")}

          />

和App.js文件在这里

import React, { Component } from 'react';
import { View,StyleSheet } from 'react-native';
import { LoginButton, AccessToken, LoginManager, } from 'react-native-fbsdk';
import { ShareApi } from 'react-native-fbsdk';
export default class App extends Component {
  componentDidNotMount() {
    LoginManager.logInWithPermissions(['public_profile']).then(
      function(result) {
        if (result.isCancelled) {
          alert('Login cancelled');
        } else {
          alert(
            'Login success with permissions: ' +
              result.grantedPermissions.toString()
          );
        }
      },
      function(error) {
        alert('Login fail with error: ' + error);
      }
    );
  }
  render() {
    return (
      <View style={styles.container}>
         <LoginButton   
          publishPermissions={["email"]}
          onLoginFinished={
            (error, result) => {
              if (error) {
                alert("Login failed with error: " + error.message);
              } else if (result.isCancelled) {
                alert("Login was cancelled");
              } else {
                alert("Login was successful with permissions: " + result.grantedPermissions)
              }
            }
          }
          onLogoutFinished={() => alert("User logged out")}

          />
      </View>
    );
  }
}
const styles = StyleSheet.create({
  container: {
    flex: 1,
    backgroundColor: '#fff',
    alignItems: 'center',
    justifyContent: 'center',
  },
});