我需要将两个SQL语句连接在一起,这两个语句都是独立工作的。但我不知道如何将这两个语句合并到一个SQL语句中。
我在第一次声明中有两个表,TR120和TR1201。
SQL是这样的:
select
PRODUCT, PRICE, QUANTITY, INVOICE.DATE
from
TR1201
left join
(select
DATE, ID as INVOICE_ID, INVOICE
from TR120) as INVOICE on INVOICE.INVOICE_ID = ID
where
INVOICE.DATE >= '2016-06-01' and INVOICE.DATE <= '2016-06-30'这是一个清单的所有产品,我出售,价格,数量和销售日期在一个特定的时间框架内,从01-06-16至30-06-16。
现在,我需要根据第一条SQL语句中的产品和销售日期,在不同的两个表中查找我购买产品的最新价格,TR100和TR1001。
select
PRODUCT, PRICE, SUP.DATE
from
TR1001
left join
(select
DATE, ID as SUP_ID, SUP_INVOICE
from TR100) as SUP on SUP.SUP_ID = ID这是一个清单,所有的产品,我已经购买了一个价格和日期。我只需要从这个查询的最后记录,根据产品和购买日期。
TR120
ID | INVOICE | DATE
1 | 000001 |2016-06-05
2 | 000002 |2016-06-15
3 | 000003 |2016-06-25TR1201
ID | PRODUCT | PRICE A | QUANTITY
1 | A | 2,00 | 5
2 | A | 2,00 | 2
3 | A | 2,00 | 1TR100
ID | SUP_INVOICE | DATE
1 | 160001 | 2016-05-30
2 | 160002 | 2016-06-16TR1001
ID | PRODUCT | PRICE B
1 | A | 0,5
2 | A | 0,7我想得到的结果是:
PRODUCT | PRICE A (tr1201) | QUANTITY | DATE (tr100) | PRICE B (tr1001)
A | 2 | 5 | 2016-05-30 | 0,5
A | 2 | 2 | 2016-05-15 | 0,5
A | 2 | 1 | 2016-05-16 | 0,7这就是我想要做的:
发布于 2016-12-21 13:48:30
你试过first_value了吗?
FIRST_VALUE ( [scalar_expression ] )
OVER ( [ partition_by_clause ] order_by_clause [ rows_range_clause ] ) 它的工作方式如下:
select distinct id,
first_value(price) over (partition by id (,sup) order by date DESC (latest, ASC for oldest)) as last_price
from table;文档可以在这里找到:https://msdn.microsoft.com/en-us/library/hh213018.aspx
发布于 2016-12-21 14:01:00
我没有你的桌子,所以不能测试,所以我只提供建议。我认为你需要的是像这样的外应用程序,而不是连接
select
T1.Product
, T1.Price
, T2.DATE -- Alias this
, T2.Price -- Alias this
, T3.DATE -- Alias this
, T3.Price -- Alias this
from T1
OUTER APPLY (
select top 1
Date
,Price
from table2
WHERE ID = T1.Id AND product = T1.Product-- plus any other joins
ORDER BY Date desc
) as T2
OUTER APPLY (
select top 1
Date
,Price
from table3
WHERE ID = T1.Id AND product = T1.Product-- plus any other joins
ORDER BY Date desc
) as T3 https://stackoverflow.com/questions/41264188
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