我们正在准备一个利克特式的天平。必须允许被试按1-9的数字.我们知道ListenChar,但它抑制了整个键盘。我们怎么能抑制非数字键?
while(1)
ch = GetChar;
if ch == 10 %return is 10 or 13
%terminate
break
else
response=[response ch];
end
end发布于 2016-12-16 22:22:25
如果您只想接受1-9键:
while(1)
ch = GetChar;
if ch == 10 %return is 10 or 13
%terminate
break
elseif (ch>48) & (ch<58) %check if the char is a number 1-9
response=[response ch];
pause(0.1) %delay 100ms to debounce and ensure that we don't count the same character multiple times
end
end我还添加了一个选项,这样您就不会意外地多次记录单个输入。
发布于 2016-12-18 20:12:18
“心理工具箱”包括通过RestrictKeysForKbCheck限制侦听特定键的功能。
以下代码限制来自1-9的可能输入,加上esc键:
KbName('UnifyKeyNames'); % use internal naming to support multiple platforms
nums = '123456789';
keynames = mat2cell(nums, 1, ones(length(nums), 1));
keynames(end + 1) = {'ESCAPE'};
RestrictKeysForKbCheck(KbName(keynames));下面是一个简单的块示例:
response = repmat('x', 1, 10); % pre-allocate response, similar to OP example
for ii = 1:10
[~, keycode] = KbWait(); % wait until specific key press
keycode = KbName(keycode); % convert from key code to char
disp(keycode);
if strcmp(keycode, 'ESCAPE')
break;
else
response(ii) = KbName(keycode);
end
WaitSecs(0.2); % debounce
end
RestrictKeysForKbCheck([]); % re-enable all keyshttps://stackoverflow.com/questions/41192671
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