我试图理解对象类的克隆()方法的工作原理。object类中的注释说‘此方法执行该对象的“浅拷贝”,而不是“深度复制”操作.’
以下是我对浅部和深版的理解。
浅层尽可能少地复制副本。集合的浅副本是集合结构的副本,而不是元素的副本。对于浅拷贝,两个集合现在共享各个元素。 深度复制复制一切。一个集合的深层副本是两个集合,其原始集合中的所有元素都被复制。
因此,如果我克隆一个对象并修改它在克隆上的任何可变元素,那么同样的元素应该反映在创建克隆的第一个对象上,因为两者共享相同的内存。为了测试这个,我创建了3个类..。
一个简单的波乔..。
package test.clone;
import java.util.Arrays;
public class Misc implements Cloneable{
private String value;
public Misc(String value) {
super();
this.value = value;
}
public String getValue() {
return value;
}
public void setValue(String value) {
this.value = value;
}
@Override
public String toString() {
return "Misc [value=" + value + "]";
}
protected Misc clone() throws CloneNotSupportedException{
return (Misc)super.clone();
}
}类需要克隆的..。
package test.clone;
import java.util.ArrayList;
import java.util.Arrays;
import java.util.List;
public class Victim implements Cloneable{
private String name = "Renjith";
private String[] educationList = {"EDU_1", "EDU_2", "EDU_3", "EDU_4"};
private Misc[] miscList = {new Misc("1"), new Misc("2")};
private List<Misc> miscList2 = new ArrayList<Misc>(Arrays.asList(miscList));
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public String[] getEducationList() {
return educationList;
}
public void setEducationList(String[] educationList) {
this.educationList = educationList;
}
protected Victim clone() throws CloneNotSupportedException{
return (Victim)super.clone();
}
public Misc[] getMiscList() {
return miscList;
}
public void setMiscList(Misc[] miscList) {
this.miscList = miscList;
}
public List<Misc> getMiscList2() {
return miscList2;
}
public void setMiscList2(List<Misc> miscList2) {
this.miscList2 = miscList2;
}
@Override
public String toString() {
return "Victim [name=" + name + ", educationList="
+ Arrays.toString(educationList) + ", miscList="
+ Arrays.toString(miscList) + ", miscList2=" + miscList2 + "]";
}
}做克隆的主类..。和修改..。
public class Main {
public static void main(String[] args) throws CloneNotSupportedException {
Victim victim = new Victim();
System.out.println(victim);
Victim secondVictim = victim.clone();
String[] educationList = {"EDU_1_mod", "EDU_2_mod", "EDU_3_mod", "EDU_4_mod"};
Misc[] miscList = {new Misc("3"), new Misc("4")};
List<Misc> miscList2 = new ArrayList<Misc>(Arrays.asList(miscList));
secondVictim.setEducationList(educationList);
secondVictim.setMiscList(miscList);
secondVictim.setMiscList2(miscList2);
System.out.println(secondVictim);
System.out.println(victim);
}
}我希望得到如下的结果..。
受害者[name=Renjith,educationList=EDU_1,EDU_2,EDU_3,EDU_4,miscList=[Misc value=1,Misc value=2],miscList2=[Misc value=1,Misc value=2]]受害者[name=Renjith,educationList=EDU_1_mod,EDU_2_mod,EDU_3_mod,EDU_4_mod,[ Misc EDU_3_mod,Misc EDU_3_mod],miscList=[Misc EDU_3_mod,Misc EDU_3_mod],[Misc,Misc]受害者[,[Misc en30#,Misc en33#],miscList2=[Misc value=3,Misc value=4]
但我有..。
受害者[name=Renjith,educationList=EDU_1,EDU_2,EDU_3,EDU_4,miscList=[Misc value=1,Misc value=2],miscList2=[Misc value=1,Misc value=2]]受害者[name=Renjith,educationList=EDU_1_mod,EDU_2_mod,EDU_3_mod,EDU_4_mod,[ Misc EDU_3_mod,Misc EDU_3_mod],miscList=[Misc EDU_3_mod,Misc EDU_3_mod],[Misc,Misc]受害者[,[Misc en30#,Misc en33#],miscList2=[Misc value=1,Misc value=2]
有人能告诉我这是怎么回事吗?
我已经通过了Understanding Object.clone() in Java,但还是无法理解.
发布于 2016-12-15 03:39:45
您不是在修改列表/数组,而是用一个新的引用来替换它们。尝试像下面这样更新您的设置:
public void setMiscList(Misc[] miscList) {
this.miscList[0] = miscList[0];
this.miscList[1] = miscList[1];
}
public void setMiscList2(List<Misc> miscList2) {
this.miscList2.set(0, miscList2.get(0));
this.miscList2.set(1, miscList2.get(1));
}这将修改共享对象,从而产生预期的输出。
https://stackoverflow.com/questions/41155969
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