python regex txt

Question

我有一个1.txt：

I. Introduction to Text Mining 1
I.1 Defining Text Mining 1
I.2 General Architecture of Text Mining Systems 13

II. Core Text Mining Operations 19
II.1 Core Text Mining Operations 19
II.2 Using Background Knowledge for Text Mining 41
II.3 Text Mining Query Languages 51

III. Text Mining Preprocessing Techniques 57
III.1 Task-Oriented Approaches 58
III.2 Further Reading 62

IV. Categorization 64
IV.1 Applications of Text Categorization 65
IV.2 Definition of the Problem 66
IV.3 Document Representation 68

我想得到这样的结果：

I. Introduction to Text Mining 1.1
    I.1 Defining Text Mining 1.1
    I.2 General Architecture of Text Mining Systems 13.1

II. Core Text Mining Operations 19.1
    II.1 Core Text Mining Operations 19.1
    II.2 Using Background Knowledge for Text Mining 41.1
    II.3 Text Mining Query Languages 51.1
...

两个变化：

1. I I.1 use the TAB.
2. all number in the end plus 0.1

我试着用熊猫，但这不是工作。我试着用别的方法，但我不知道怎么写下一个程序：

# -*- coding: utf-8 -*-
import re

f=open("D:/Downloads/1.txt")
page_list = []
content=[]
for line in f:
    if re.search('(\d+)$',line) !=None:
        page_list.append(re.search('(\d+)$',line).group())
    if re.search('^(.*\.\d+)',line) !=None:
        content.append(re.search('^(.*\.\d+)',line).group())
str=map(lambda x:x+'.1',page_list)
print str
con=map(lambda x:'\t'+x,content)
print con

该方案的结果：

['1.1', '1.1', '13.1', '19.1', '19.1', '41.1', '51.1']
['\tI.1', '\tI.2', '\tII.1', '\tII.2', '\tII.3']

Answer 1

你可以试试这个：

(.*)(\d+)

并以下列案文取代：

\1\2.1

解释

样本代码：

import re

regex = r"(.*)(\d+)"

test_str = ("I. Introduction to Text Mining 1\n"
    "I.1 Defining Text Mining 1\n"
    "I.2 General Architecture of Text Mining Systems 13\n\n"
    "II. Core Text Mining Operations 19\n"
    "II.1 Core Text Mining Operations 19\n"
    "II.2 Using Background Knowledge for Text Mining 41\n"
    "II.3 Text Mining Query Languages 51\n\n"
    "III. Text Mining Preprocessing Techniques 57\n"
    "III.1 Task-Oriented Approaches 58\n"
    "III.2 Further Reading 62\n\n"
    "IV. Categorization 64\n"
    "IV.1 Applications of Text Categorization 65\n"
    "IV.2 Definition of the Problem 66\n"
    "IV.3 Document Representation 68\n\n")

subst = "\\1\\2.1"


result = re.sub(regex, subst, test_str, 0, re.MULTILINE)

if result:
    print (result)

样本输出：

I. Introduction to Text Mining 1.1
I.1 Defining Text Mining 1.1
I.2 General Architecture of Text Mining Systems 13.1

II. Core Text Mining Operations 19.1
II.1 Core Text Mining Operations 19.1
II.2 Using Background Knowledge for Text Mining 41.1
II.3 Text Mining Query Languages 51.1

III. Text Mining Preprocessing Techniques 57.1
III.1 Task-Oriented Approaches 58.1
III.2 Further Reading 62.1

IV. Categorization 64.1
IV.1 Applications of Text Categorization 65.1
IV.2 Definition of the Problem 66.1
IV.3 Document Representation 68.1

Answer 2

对于TAB缩进，可以使用以下代码：

for m in re.finditer(r'[IVX]+\.\d.*\n',result):
  oldgroup = m.group()
  newgroup = '\t' + oldgroup
  result = re.sub(oldgroup,newgroup,result)