减法浮子场odoo 9

Question

如何在功能上减去两个浮点字段“完成-启动”

start = fields.Float(string='Star')
finish = fields.Float(string='Fin')
total = fields.Float(string='Total')

    @api.one
       def total_sum(self):
       ?????? 

Answer 1

应该是这样，

total = fields.Float(string='Total', compute=_set_total)

@api.multi
def _set_total(self):
    for rec in self:
        rec.total = float(rec.finish or 0.0) - float(rec.start or 0.0)

但是，您也可以创建正常的字段，而不是功能字段。

total = fields.Float(string='Total')

@api.onchange('finish','start')
def _set_total(self):
    self.total = float(self.finish or 0.00) - float(self.start or 0.00)

Answer 2

def total_sum(self, cr, uid, ids, start, finish, context=None):
    res = {}
    res['total'] = finish - start
    return {'value': res}