我从.txt文件中引入值并将它们放入数组中,但最终存储在数组中的数字与文件中的值不同,我不知道为什么以及如何修复它。
文本文件是用以下值排列的
2
20.0
10.0
100将值导入文件的方法是:
//variables global to the class
public static int level;
public static int hp;
public static double vigor;
public static double intelligence;
public static void checkSaveState() throws IOException
{
//this method checks the save file for data
try
{
double[] savedGa = new double[4];
BufferedReader saveFile = new BufferedReader(new FileReader("HRHeroSaveGame.txt"));
for (int i = 0; i < 4; i++)
{
savedGa[i] = saveFile.read();
}
level = (int) savedGa[0];
vigor = savedGa[1];
intelligence = savedGa[2];
hp = (int) savedGa[3];
System.out.println("Level: " + level + " Vigor: " + vigor + " Intelligence: " + intelligence + " HP: " + hp);
} catch (FileNotFoundException e) {
System.out.println("Sorry, a save file couldn't be found for you.");
}
}输出结果总是这样:
Level: 50 Vigor: 13.0 Intelligence: 10.0 HP: 50如果这与此相关,这就是创建文件的方法。
public static void saveGame() throws IOException
{
PrintWriter saveFile = new PrintWriter( new FileWriter("HRHeroSaveGame.txt"));
saveFile.println(level);
saveFile.println(vigor);
saveFile.println(intelligence);
saveFile.println(hp);
saveFile.close();
}发布于 2016-12-13 16:26:32
read()只读取一个字符。这解释了您的结果:'2' = 50,'\r' = 13,'\n' = 10
您必须将每一行读入为String,并对其进行解析以获得加倍:
savedGa[i] = Double.parseDouble(saveFile.readLine());发布于 2016-12-13 16:27:40
BufferReader的read()方法读取字符的整数表示,而不是转换为double或int的完整行。
要解决这个问题,只需将for-循环更改为
try
{
double[] savedGa = new double[4];
BufferedReader saveFile = new BufferedReader(new FileReader("C:/test.txt"));
for (int i = 0; i < 4; i++)
{
savedGa[i] = Double.parseDouble(saveFile.readLine());
}
level = (int) savedGa[0];
vigor = savedGa[1];
intelligence = savedGa[2];
hp = (int) savedGa[3];
System.out.println("Level: " + level + " Vigor: " + vigor + " Intelligence: " + intelligence + " HP: " + hp);
} catch (FileNotFoundException e) {
System.out.println("Sorry, a save file couldn't be found for you.");
}它将整行读取为字符串,然后将其解析为double。
https://stackoverflow.com/questions/41125742
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