java.lang.IllegalArgumentException:注册名为“dispatcher”的servlet失败。

Question

我的初始化器类

public class HomeServlet extends 
AbstractAnnotationConfigDispatcherServletInitializer{

@Override
protected Class<?>[] getRootConfigClasses() {

    return null;
}

@Override
protected Class<?>[] getServletConfigClasses() {

    return new Class<?>[]{SpringContextConfig1.class};
}

@Override
protected String[] getServletMappings() {

    return new String[] {"/home"};
}

}

配置类

@ComponentScan(basePackages={"spittr.controllers"})
@Configuration
@EnableWebMvc
public class SpringContextConfig1 extends WebMvcConfigurerAdapter{

@Bean
public ViewResolver getViewResolver(){
    InternalResourceViewResolver ivr=new InternalResourceViewResolver();
    ivr.setPrefix("/WEB-INF/jsp/");
    ivr.setSuffix(".jsp");
    ivr.setExposeContextBeansAsAttributes(true);
    return ivr;
}

}

控制器

@Controller
public class HomeController {


@RequestMapping(value="/home",method=RequestMethod.GET)
public String home(){
    return "home";
}

}

这是一个非常简单的程序，我编写来测试Spring的JavaConfig，我完全遵循了"Spring“一书中的所有步骤。

当我运行这段代码时，我会得到这个错误

09:41:37,854错误jboss.undertow.deployment.default-server.default-host./spittr: MSC000001:未能在服务jboss.undertow.deployment.default-server.default-host./spittr: java.lang.RuntimeException中启动服务org.jboss.msc.service.fail org.jboss.msc.service.StartException : java.lang.IllegalArgumentException:未能注册名为“dispatcher”的servlet。在org.wildfly.extension.undertow.deployment.UndertowDeploymentService$1.run(UndertowDeploymentService.java:85) at java.util.concurrent.Executors$RunnableAdapter.call(Executors.java:511) at java.util.concurrent.FutureTask.run(FutureTask.java:266) at java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1142) at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:617) at java.lang.Thread.run(Thread.java:745)在org.jboss.threads.JBossThread.run(JBossThread.java:320)，由: java.lang.RuntimeException: java.lang.IllegalArgumentException:未能注册名为“dispatcher”的servlet。检查是否有另一个servlet以相同的名称注册。在io.undertow.servlet.core.DeploymentManagerImpl.deploy(DeploymentManagerImpl.java:236) at org.wildfly.extension.undertow.deployment.UndertowDeploymentService.startContext(UndertowDeploymentService.java:100) at org.wildfly.extension.undertow.deployment.UndertowDeploymentService$1.run(UndertowDeploymentService.java:82) .6更多的原因是: java.lang.IllegalArgumentException:未能注册名为“dispatcher”的servlet。在org.springframework.util.Assert.notNull(Assert.java:115) at org.springframework.web.servlet.support.AbstractDispatcherServletInitializer.registerDispatcherServlet(AbstractDispatcherServletInitializer.java:98) at org.springframework.web.servlet.support.AbstractDispatcherServletInitializer.onStartup(AbstractDispatcherServletInitializer.java:71) at org.springframework.web.SpringServletContainerInitializer.onStartup(SpringServletContainerInitializer.java:169) at io.undertow.servlet.core.DeploymentManagerImpl$1.call(DeploymentManagerImpl.java:186) at io.undertow.servlet.core.DeploymentManagerImpl$1io.undertow.servlet.core.ServletRequestContextThreadSetupAction$1.call(ServletRequestContextThreadSetupAction.java:42) at io.undertow.servlet.core.ContextClassLoaderSetupAction$1.call(ContextClassLoaderSetupAction.java:43) io.undertow.servlet.api.LegacyThreadSetupActionWrapper$1.call(LegacyThreadSetupActionWrapper.java:44) at io.undertow.servlet.api.LegacyThreadSetupActionWrapper$1.call(LegacyThreadSetupActionWrapper.java:44) at io.undertow.servlet.api.LegacyThreadSetupActionWrapper$1.call(LegacyThreadSetupActionWrapper.java:44) .call(DeploymentManagerImpl.java:171)在io.undertow.servlet.api.LegacyThreadSetupActionWrapper$1.call(LegacyThreadSetupActionWrapper.java:44) at io.undertow.servlet.api.LegacyThreadSetupActionWrapper$1.call(LegacyThreadSetupActionWrapper.java:44) at io.undertow.servlet.core.DeploymentManagerImpl.deploy(DeploymentManagerImpl.java:234)

错误的最大亮点是，org.wildfly.extension.undertow.deployment.UndertowDeploymentService$1.run(UndertowDeploymentService.java:85)“未能注册名为‘dispatcher’的servlet。检查是否有另一个servlet以相同的名称注册。”

请帮我解决这个问题。我在月食上使用了WildFly-10。

Answer 1

1. 按照以下方式使用配置类： @ComponentScan(basePackages={"spittr.controllers"}) @Configuration @EnableWebMvc公共类SpringContextConfig1扩展了WebMvcConfigurerAdapter{ @覆盖公共无效configureViewResolvers(ViewResolverRegistry注册表){ InternalResourceViewResolver ivr=new InternalResourceViewResolver()；ivr.setPrefix(“/WEB/jsp/”)；ivr.setSuffix(".jsp")；ivr.setExposeContextBeansAsAttributes(真)；registry.viewResolver(ivr)；}} 基本上，您是在不继承任何方法的情况下扩展WebMvcConfigurerAdapter的(至少在我的4.3.3Spring版本中)。
2. 由于这里有一个DispatcherServlet，所以可以将SpringContextConfig1类添加到根上下文中，并将servlet上下文保持为空:将方法getServletConfigClasses()的主体切换到getRootConfigClasses()下面，反之亦然--参见等级制度。

此外，DispatcherServlet映射更可能是/而不是/home。

protected String[] getServletMappings() {
    return new String[] {"/"};
}

Answer 2

我的朋友也遇到了同样的问题。问题是没有为类设置正确的包名。AAAAnd包装前清洁项目！

以下是GitHub上的代码