如何合并这两个forEach循环(只使用一个)？

Question

下面的代码接受两个数组(fields和photos)，获取它们的字段的名称和值，并将它们添加到一个新数组(panoramas)中：

函数：

const panoramas = this.uploads.finished.map(photos => {
   let panorama = {}
   fields.forEach(field => { panorama[field.name] = field.value })
   photos.forEach(photo => { panorama[photo.name] = photo.value })
   return panorama
})

输入：

fields

[{
  name: "name"
  type: "hidden"
  value: ""
}, {
  name: "description"
  type: "hidden"
  value: ""
}, {
  name: "photo"
  type: "file"
  value: ""
}, {
  name: "photo2"
  type: "file"
  value: ""
}]

photos

[{
  name: "photo"
  value: "1.png"
}, {
  name: "photo2"
  value: "2.jpg"
}]

输出：

panoramas:

[{
  name: "name"
  type: "hidden"
  value: ""
}, {
  name: "description"
  type: "hidden"
  value: ""
}, {
  name: "photo"
  type: "file"
  value: "1.png"
}, {
  name: "photo2"
  type: "file"
  value: "2.png"
}]

如您所见，我在map中使用两个map循环。有没有办法只使用一个forEach

Answer 1

fields.concat(photos).forEach(obj => { panorama[obj.name] = obj.value });