javascript regex忽略chokidar的子目录

Question

目前使用Chokidar对文件结构进行文件监视。我需要查看特定目录，但忽略该目录中创建的任何子目录。

例如,

/var/app/current/somedir

我会看到在中创建的任何文件。但是，如果在目录中创建了某个目录，那么我希望递归地忽略它，从而忽略它下创建的任何其他内容。

chokidar.watch(configuration.theDir, {
        ignored: `/\\var\\app\\current\\somedir\\<match anything here, except other directories!>\\<anything here would be ignored and further down...>/`,
        awaitWriteFinish: {
            stabilityThreshold: 2000,
            pollInterval: 100
        }
}).on('add', (file, details) => {
    // console.log(file, path);
});

对于我来说，找到正确实现正则表达式的方法是真实的。不幸的是，创建的目录是随机的，名称事先不知道。这能做到吗？

Answer 1

这个regex表达式将匹配是一个目录或属于基的子目录(由下面的斜杠/定义的目录)的所有内容。

对于您的示例，基础是：/var/app/current/somedir

Regex：/^\/var\/app\/current\/somedir\/.*[\/].*$/i

测试：

var tests = [
    '/var/app/current/somedir/fileOrFolder.txt',
    '/var/app/current/somedir/fileOrFolder/',
    '/var/app/current/somedir/fileOrFolder/ssads/sad.s',
    '/var/app/current/somedir/fileOrFolder.sd/sdasda.asda/',
    '/var/app/current/somedir/fileOrFolder.txt',
    '/var/app/current/somedir/fileOrFolder'
]

for (var ii = 0, nn = tests.length; ii < nn; ii++)
{
    if (/^\/var\/app\/current\/somedir\/.*[\/].*$/i.test(tests[ii]))
    {
        console.log('"'+tests[ii]+'"', 'Matched, so ignored.');
    }
    else
    {
        console.log('"'+tests[ii]+'"', 'Not matched, so watch.');
    }
}

在JavaScript控制台中打印以下内容：

/*
 * "/var/app/current/somedir/fileOrFolder.txt" Not matched, so watch.
 * "/var/app/current/somedir/fileOrFolder/" Matched, so ignored.
 * "/var/app/current/somedir/fileOrFolder/ssads/sad.s" Matched, so ignored.
 * "/var/app/current/somedir/fileOrFolder.sd/sdasda.asda/" Matched, so ignored.
 * "/var/app/current/somedir/fileOrFolder.txt" Not matched, so watch.
 * "/var/app/current/somedir/fileOrFolder" Not matched, so watch.
*/