检查PHP中是否存在pear键

Question

为新手的问题道歉，但我对PHP还比较陌生，我想做一些相当简单的事情.如果我有一个键和值数组(梨)：

$arrayOfPears = array(
                      "Green Anjou" => [ 7,
                                         "plump",
                                         "ripe",
                                         "juicy",
                                         "green"
                                        ],
                      "Bartlett"     => [ 2,
                                          "moderately plump",
                                          "unripe",
                                          "sweet",
                                          "greeny-yellow"
                                         ],
                      "Comice"       =>  [ 3,
                                           "rather plump",
                                           "ripe",
                                           "blinding",
                                           "deep-green"
                                         ],
                      "Plum"          => [ 6,
                                           "rotund",
                                           "over-ripe",
                                           "sweet",
                                           "purple",
                                           "not really a pear, as far as I'm aware"
                                          ]
                      );

我能够访问特定pear的值，并将其用于比较操作。例如：

if($arrayofPears['Comice'][2] == "ripe") {
   $nibble = true;
   return $nibble;
}

返回一个真正的$nibble。但是，我想要做的是先检查数组中是否存在Comise键，然后尝试输入if语句并确定是否得到了真正的$nibble。

所以..。在承诺输入条件之前，如何检查在这种情况下是否存在“Comice”？

Answer 1

你可以试试这个：

if(array_key_exists("Comice",$arrayOfPear){
//Do the Loop
}
else{
//Don't enter the loop
}