每次在登录页面加载消息时,显示入侵登录。它不是检查if条件是否直接转到。我重复我的sql查询,它运行得很好。但我不明白我在哪里出了错。你能帮帮我吗。
我下面的代码,
<?php
#$error = "";
$servername = "localhost";
$username = "";
$password = "";
$dbname = "lg_db";
$tb_name = "lgin";
mysql_connect("$servername", "$username", "$password")or die("Cannot connect");
mysql_select_db("$dbname")or die("Cannot connect to Database");
$username = $_POST['username'];
$pass = $_POST['password'];
$username=stripslashes($username);
$pass=stripslashes($pass);
$username=mysql_real_escape_string($username);
$pass=mysql_real_escape_string($pass);
$sql="SELECT * FROM $tb_name WHERE Name='$username' and Password='$pass'";
$result=mysql_query($sql);
$count1=mysql_num_rows($result);
if($count1 >=1)
{
session_start();
$_SESSION['simple_login'] = $username;
header("Location: index_new.php");
exit();
}else{
$error="Invalid Login";
}
?>发布于 2016-11-25 08:42:47
感谢您的支持和帮助!我的问题解决了。我已经添加了if($_SERVER["REQUEST_METHOD"] == "POST"),并在此之前添加了html文件中的数据。
https://stackoverflow.com/questions/40791908
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