使用Google-Drive-API移动文件

Question

是否可以通过python的googleapiclient模块显式地移动文件？我希望创建以下函数，给定一个文件、原始路径和目标路径：

def move_file(service, filename, init_drive_path, drive_path, copy=False):
    """Moves a file in Google Drive from one location to another.

    service: Drive API service instance.
    filename (string): full name of file on drive
    init_drive_path (string): initial file location on Drive
    drive_path (string): the file path to move the file in on Drive
    copy (boolean): file should be saved in both locations

    Returns nothing.
    """

目前，我一直通过手动下载文件并将其重新上传到所需位置来执行此操作，但是这对于大文件来说并不实用，而且似乎是一种变通的方法。

这是文件用于google上可用的方法。

编辑--见下面的解决方案：

Answer 1

在这里找到的。只需检索文件和文件夹ID，然后使用update方法即可。如果要将文件的副本保留在旧文件夹中，则可以排除remove_parents参数。

    file_id = '***'
    folder_id = '***'

    # Retrieve the existing parents to remove
    file = drive_service.files().get(fileId=file_id, fields='parents').execute()
    previous_parents = ",".join(file.get('parents'))

    # Move the file to the new folder
    file = drive_service.files().update(
        fileId=file_id,
        addParents=folder_id,
        removeParents=previous_parents,
        fields='id, parents'
    ).execute()

(注意，我没有包含我的基本助手函数_getFileId和_getFolderId)，所以我的原始函数看起来如下所示：

    def move_file(service, filename, init_drive_path, drive_path, copy=False):
        """Moves a file in Google Drive from one location to another.
    
            service: Drive API service instance.
            'filename' (string): file path on local machine, or a bytestream
            to use as a file.
            'init_drive_path' (string): the file path the file was initially in on Google
            Drive (in <folder>/<folder>/<folder> format).
            'drive_path' (string): the file path to move the file in on Google
            Drive (in <folder>/<folder>/<folder> format).
            'copy' (boolean): file should be saved in both locations
    
            Returns nothing.
        """
        file_id = _getFileId(service, filename, init_drive_path)
        folder_id = _getFolderId(service, drive_path)
    
        if not file_id or not folder_id:
            raise Exception('Did not find file specefied: {}/{}'.format(init_drive_path, filename))
    
        file = service.files().get(fileId=file_id, fields='parents').execute()
        
        if copy:
            previous_parents = ''
        else:
            previous_parents = ",".join(file.get('parents'))

        file = drive_service.files().update(
            fileId=file_id,
            addParents=folder_id,
            removeParents=previous_parents,
            fields='id, parents'
        ).execute()