使用imaplib获取错误

Question

我正在写一个脚本，通过我的电子邮件来计算我在优步上总共花了多少钱。(Uber给你的电子邮件发了一张收据，其中包括了费用。我正在查看电子邮件以查找成本，然后将其添加到当前的数组中)，我让它使用1封电子邮件进行测试，但在试图遍历所有电子邮件时遇到了一个问题。

我知道id_list(电子邮件I列表)是一个完整的数组。当我打印出来时，我收到：['4726', '5543', '5587', '5589', '5661', '5758', '5759', '5853', '5986', '6071', '6072', '6076', '6105', '6141', '6229']

以下是我的完全错误跟踪：

Traceback (most recent call last):
  File "/Users/Harrison/Desktop/Uber/Uber.py", line 22, in <module>
    result,data = mail.fetch(id, "(RFC822")
  File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/imaplib.py", line 456, in fetch
    typ, dat = self._simple_command(name, message_set, message_parts)
  File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/imaplib.py", line 1088, in _simple_command
    return self._command_complete(name, self._command(name, *args))
  File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/imaplib.py", line 918, in _command_complete
    raise self.error('%s command error: %s %s' % (name, typ, data))
imaplib.error: FETCH command error: BAD ['Could not parse command']

这是我的密码：

import imaplib
import email
from bs4 import BeautifulSoup

final_cost1 = ""
final_cost2 = ""

cost_array = []

mail = imaplib.IMAP4_SSL('imap.gmail.com')
mail.login('my email', 'my passowrd')

mail.list()
mail.select('inbox')
result,data = mail.search(None, 'FROM', '"Uber Receipts"')

ids = data[0]
id_list = ids.split()


for id in id_list:
    result,data = mail.fetch(id, "(RFC822")

    message_body = data[0][1]

    uber_email = email.message_from_string(message_body)
    for part in uber_email.walk():
        if part.get_content_type() == "text/html":
            body = part.get_payload(None, decode=True)

    soup = BeautifulSoup(body, 'html.parser')
    #print soup.prettify()

    for row in soup.find_all('td', attrs={"class" : "price final-charge"}):
        final_cost1 = row.text.lstrip().strip()

    for row in soup.find_all('td', attrs={"class" : "totalPrice chargedFare black"}):
        final_cost2 = row.text.lstrip().strip()

    if final_cost1 != "":
        print final_cost1
        cost_array.append(final_cost1)
    if final_cost2 != "":
        print final_cost2
        cost_array.append(final_cost2)

print cost_array

Answer 1

我犯了个愚蠢的错误。

这一行result,data = mail.fetch(id, "(RFC822")有一个错误。应该是result,data = mail.fetch(id, "(RFC822)")