我正在使用angular2开发一个应用程序。目前,我正试图找出如何使用angular2-mdl制作动态下拉菜单,但我似乎无法找到正确的解决方案。下面是我的项目的代码片段
<nav class="mdl-navigation mdl-layout--large-screen-only">
<ng-container *ngFor="let link of links; let i = index">
<ng-container *ngIf="!link.hasSubLinks()">
<button mdl-button class="mdl-navigation__link" (click)="route(link.url)" [routerLink]="link.url" routerLinkActive="active">
{{link.name}}
</button>
</ng-container>
<ng-container *ngIf="link.hasSubLinks()">
<button mdl-button class="mdl-navigation__link" #{{link.name}}="mdlButton" [mdl-toggle-menu]="submenu">
{{link.name}}
</button>
<mdl-menu #submenu="mdlMenu" mdl-menu-position="bottom-right" class="mdl-color--blue-grey-800">
<mdl-menu-item *ngFor="let subLink of link.subLinks">
<a class="mdl-navigation__link" [routerLink]="subLink.url" routerLinkActive="active">
<mdl-icon mdl-list-item-icon [mdl-badge]="subLink.badge>0?subLink.badge:null" mdl-badge-overlap role="presentation" class="colorwhite">{{subLink.icon}}</mdl-icon>{{subLink.name}}
</a>
</mdl-menu-item>
</mdl-menu>
</ng-container>
</ng-container>
</nav>它似乎不像我期望的工作方式,在材料设计精巧的菜单页面,当我点击一个菜单,另一个关闭。所发生的是,我可以打开所有下拉菜单,但当我试图关闭一个,他们都关闭。我认为我的问题是<button ... [mdl-toggle-menu]="submenu">和<mdl-menu #submenu="mdlMenu" ... >是否有一种方法来动态地为它设置值?
我尝试将值更改为<button ... [mdl-toggle-menu]="link.icon">和<mdl-menu #{{link.icon}}="mdlMenu" ... >,但我得到了一个错误。有什么想法吗?
error_handler.js:54 TypeError: this.menu.toggle is not a function
at MdlToggleMenuDirective.onClick (mdl-toggle-menu.directive.js:11)
at _View_AppComponent3._handle_click_2_2 (component.ngfactory.js:1162)
at view.js:375
at dom_renderer.js:262
at dom_events.js:30
at ZoneDelegate.invoke (zone.js:232)
at Object.onInvoke (ng_zone.js:238)
at ZoneDelegate.invoke (zone.js:231)
at Zone.runGuarded (zone.js:128)
at NgZone.runGuarded (ng_zone.js:133)编辑
谢谢你的模板..。下面是柱塞代码http://plnkr.co/edit/R6Bnadu124qOohjUWuMZ?p=preview
发布于 2016-11-14 08:39:43
你一切都做对了。在angular2-mdl中有一个bug :如果打开另一个菜单(刚刚创建:https://github.com/mseemann/angular2-mdl/issues/200),打开的菜单将不会关闭。
解决办法是:在打开菜单的每个按钮上注册一个单击事件侦听器:
<button mdl-button (click)="hideAllExcept(submenu)" class="mdl-navigation__link" #{{link.name}}="mdlButton" [mdl-toggle-menu]="submenu">{{link.name}}</button>在应用程序组件中查询所有menuComponents:
@ViewChildren(MdlMenuComponent) private menuComponents: QueryList<MdlMenuComponent>;并隐藏除将打开的菜单外的所有菜单:
hideAllExcept(submenu) {
this.menuComponents.forEach( (menu) => {
if (submenu !== menu) {
menu.hide();
}
});
}下面是解决方法的plnkr:http://plnkr.co/edit/Yo7F1HKZSmVU309selTc?p=info
https://stackoverflow.com/questions/40542843
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