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社区首页 >问答首页 >RxPy -把实时推特流变成Rx可以观察到的?

RxPy -把实时推特流变成Rx可以观察到的?
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Stack Overflow用户
提问于 2016-11-09 01:40:42
回答 1查看 1.2K关注 0票数 2

我沿着这个伟大的教程,使用tweepy利用Python中的实时Twitter流。这将在直播时打印提到RxJava、RxPy、RxScala或ReactiveX的推特。

代码语言:javascript
复制
from tweepy.streaming import StreamListener
from tweepy import OAuthHandler
from tweepy import Stream
from rx import Observable, Observer

#Variables that contains the user credentials to access Twitter API
access_token = "CONFIDENTIAL"
access_token_secret = "CONFIDENTIAL"
consumer_key = "CONFIDENTIAL"
consumer_secret = "CONFIDENTIAL"


#This is a basic listener that just prints received tweets to stdout.
class TweetObserver(StreamListener):

    def on_data(self, data):
        print(data)
        return True

    def on_error(self, status):
        print(status)



if __name__ == '__main__':

    #This handles Twitter authetification and the connection to Twitter Streaming API
    l = TweetObserver()
    auth = OAuthHandler(consumer_key, consumer_secret)
    auth.set_access_token(access_token, access_token_secret)
    stream = Stream(auth, l)

    #This line filter Twitter Streams to capture data by the keywords: 'python', 'javascript', 'ruby'
    stream.filter(track=['rxjava','rxpy','reactivex','rxscala'])

这是通过ReactiveX可以观察到的转化为RxPy的完美候选。但是,我到底该如何把它变成一个热源Observable呢?我似乎找不到任何关于如何执行Observable.create()的文档.

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回答 1

Stack Overflow用户

回答已采纳

发布于 2016-12-01 06:25:04

我一段时间前就知道了。您必须定义一个操作传递的Observer参数的函数。然后你把它传递给Observable.create()

代码语言:javascript
复制
from tweepy.streaming import StreamListener
from tweepy import OAuthHandler
from tweepy import Stream
import json
from rx import Observable

# Variables that contains the user credentials to access Twitter API
access_token = "PUT YOURS HERE"
access_token_secret = "PUT YOURS HERE"
consumer_key = "PUT YOURS HERE"
consumer_secret = "PUT YOURS HERE"


def tweets_for(topics):
    def observe_tweets(observer):
        class TweetListener(StreamListener):
            def on_data(self, data):
                observer.on_next(data)
                return True

            def on_error(self, status):
                observer.on_error(status)

        # This handles Twitter authetification and the connection to Twitter Streaming API
        l = TweetListener()
        auth = OAuthHandler(consumer_key, consumer_secret)
        auth.set_access_token(access_token, access_token_secret)
        stream = Stream(auth, l)
        stream.filter(track=topics)

    return Observable.create(observe_tweets).share()


topics = ['Britain', 'France']

tweets_for(topics) \
    .map(lambda d: json.loads(d)) \
    .subscribe(on_next=lambda s: print(s), on_error=lambda e: print(e))
票数 4
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页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/40499153

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